pass datagridview between two forms

Question

I want to pass datagridview from this form 'itemsManagement' to 'editItems' form public partial class itemsManagement : Form { public itemsManagement() { InitializeComponent(); this.ActiveForms = new Dictionary (); } private Dictionary ActiveForms; private void showform () where TSource : Form { Form form = null; if (this.ActiveForms.ContainsKey(typeof(TSource))) { form = this.ActiveForms[typeof(TSource)]; form.WindowState = FormWindowState.Normal; form.ShowDialog(); } else { form = Activator.CreateInstance (); form.FormClosed += form_FormClosed; form.ShowDialog(); this.ActiveForms.Add(typeof(TSource), form); } } private void form_FormClosed(object sender, FormClosedEventArgs e) { this.ActiveForms.Remove(sender.GetType()); } private void editItemToolStripMenuItem_Click(object sender, EventArgs e) { this.showform (); } please help me

Rafnas T P · Answer

try like this PAL.editItems pal = new PAL.editItems(); pal.txt_itemNo.Text = this.dgv_items.CurrentRow.Cells[0].Value.ToString(); //assign before call //.... this.showform ();

mohammad amrat · Answer

request from me as this By using dictionary in past I am using public partial class itemsManagement : Form { private static itemsManagement frm; static void frm_FormClosed(object sender, FormClosedEventArgs e) { frm = null; } public static itemsManagement getMainForm { get { if (frm == null) { frm = new itemsManagement (); frm.FormClosed += new FormClosedEventHandler(frm_FormClosed); } return frm; } } public itemsManagement () { InitializeComponent(); if (frm == null) { frm = this; } } private void editToolStripMenuItem_Click(object sender, EventArgs e) { edititem x = new edititem(); x.textBox1.Text = this.dataGridView1.CurrentRow.Cells[0].Value.ToString(); x.textBox2.Text = this.dataGridView1.CurrentRow.Cells[1].Value.ToString(); x.textBox3.Text = this.dataGridView1.CurrentRow.Cells[2].Value.ToString(); x.textBox4.Text = this.dataGridView1.CurrentRow.Cells[3].Value.ToString(); x.textBox5.Text = this.dataGridView1.CurrentRow.Cells[4].Value.ToString(); x.textBox6.Text = this.dataGridView1.CurrentRow.Cells[5].Value.ToString(); x.textBox7.Text = this.dataGridView1.CurrentRow.Cells[6].Value.ToString(); x.textBox8.Text = this.dataGridView1.CurrentRow.Cells[7].Value.ToString(); x.ShowDialog(); }

Rafnas T P · Answer

have you changed code in edititems form as below change public DataGridView dg to public DataGridView dg=new DataGridView(); if not please change and let me know what is the output

mohammad amrat · Answer

An unhandled exception of type 'System.NullReferenceException' occurred in store_project.exe this error becuase PAL.editItems pal = new PAL.editItems(); pal.dg = dgv_items; pal object different of object created and opened in showform() function so dg is null

mohammad amrat · Answer

I am try public partial class editItems : Form { public DataGridView dg; //... } and in itemsManagement screen private void editItemToolStripMenuItem_Click(object sender, EventArgs e) { PAL.editItems pal = new PAL.editItems(); pal.dg = dgv_items; this.showform (); //.............. } but error occur

Rafnas T P · Answer

try like this in editItems declare public gridview as below public partial class editItems : Form { public DataGridView dg; //... } and in itemsManagement screen private void editItemToolStripMenuItem_Click(object sender, EventArgs e) { PAL.editItems pal = new PAL.editItems(); pal.dg = dgv_items; this.showform (); //.............. }

Rafnas T P · Answer

if your problem got solved then please check accepted

Rafnas T P · Answer

you can do like this for example from Form1 I am passing frmdg grid to Form2 when you opening Form2 from Form1 as follows Form2 frm2 = new Form2 ( frmdg ); //grid name- frmdg in Form1 frm2 .ShowDialog(); in Form2 loading constructor you have to change as below public partial class Form2 : Form { public Form2 (DataGridView dg) //dg is your datagrid view from Form1 { InitializeComponent(); //..... } }

mohammad amrat · Answer

HI this is code as rar

Nilesh Shah · Answer

which is the variable name for gridview? can you post your code as rar or zip file attachment

Rafnas T P · Answer

why do you want to use dictionary only

mohammad amrat · Answer

I want to pass datagridview from this form "itemsManagement" to "editItems" form why ?? to fill controls(TextBoxes ,Picture Box,TimeDatePicker) in "editItems" form with the value of current Row of datagridview in "itemsManagement" form I can do this as below in normal situation ( PAL : i s a namespace , dgv_items : is the name of datagrid in "itemsManagement" form ) : private void editItemToolStripMenuItem_Click(object sender, EventArgs e) { PAL. edititems edititem = new PAL . edititems(); edititem. txt_itemNo.Text = this.dgv_items.CurrentRow.Cells[0].Value.ToString(); edititem. txt_itemName.Text = this.dgv_items.CurrentRow.Cells[1].Value.ToString(); ........ elc edititem. ShowDialog(); } but when I use dictionary to show forms : this.ActiveForms = new Dictionary (); private Dictionary ActiveForms; private void showform () where TSource : Form { Form form = null; if (this.ActiveForms.ContainsKey(typeof(TSource))) { form = this.ActiveForms[typeof(TSource)]; form.WindowState = FormWindowState.Normal; form.ShowDialog(); } else { form = Activator.CreateInstance (); form.FormClosed += form_FormClosed; form.ShowDialog(); this.ActiveForms.Add(typeof(TSource), form); } } private void form_FormClosed(object sender, FormClosedEventArgs e) { this.ActiveForms.Remove(sender.GetType()); } I can not do this !!!

Rafnas T P · Answer

public DataGridView dg to public DataGridView dg=new DataGridView(); it will work

Rafnas T P · Answer

what error you got

mohammad amrat · Answer

my problem was not solved

mohammad amrat · Answer

Thanks Rafnas but this in the normal case but here I am using dictionary

pass datagridview between two forms

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Answers (16)