What is LINQ and Array Processing Using LINQ

This article shows how a LINQ query can process a simple integer array using the C# programming language with nice examples.

What is LINQ?

LINQ is the acronym for Language Integrated Query. LINQ is a Microsoft technology to perform operations on nearly all data sources. Here I have described nearly all data sources. Yes it supports General Arrays, Generic Lists, XML, Databases and even flat files. The beauty of LINQ is uniformity. Now, how does it provide uniformity?

Using a single LINQ query you can process data in various data sources. You may change your data set without changing the LINQ query to process the data.

Now before going into deep discussion, I would like to tell you that this article is not intended to discuss the basic concepts of LINQ or its advantages or disadvantages. Here I would like to show how a LINQ query can process a simple integer array using the C# programming language with nice examples.

Process integer array with LINQ.

The following code displays all items of an Array:

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = from n in numbers

                     select n;

    Console.WriteLine("Print all number");

    foreach (var x in lowNums)

    {

       Console.WriteLine(x);

    }

    Console.ReadLine();
}


If you want to display only even numbers then use a where clause in the LINQ query:
 

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                   where(n % 2 == 0)

                   select n);

 

    Console.WriteLine("Select even number only");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

Sometimes its necessary to sort an item by a sorting condition, here the code will Print all items where the item is greater than 5:
 

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                   where(n % 2 != 0)

                   select n);

 

    Console.WriteLine("Select even number only");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

We can specify more than one condition using an "and" ("&&") operation as in the following. This code will Print all items where the item is greater than 5 and less than 7:

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = from n in numbers

                 where n>5

                 select n;

    Console.WriteLine("Print all item where item is greater than 5");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

    onsole.ReadLine();

 }

We can specify an "or" ("||") operation in our LINQ query like in the code below. The code below will print all items where the item is greater than 5 and less than 7:

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = from n in numbers

                  where (n>5 && n<7)

                  select n;

    Console.WriteLine("Print item where item is greater than 5 and less than 7");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

    Console.ReadLine();

}

We can check equality using the "=" operator to find an exact match with our search criteria. The code below will display the items where the item value is 0.

static void Main(string[] args)
{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = from n in numbers

        where (n>5 && n<7)

        select n;


    Console
.WriteLine("Print item where item is greater than 5 or greater than 7");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

        Console.ReadLine();

}


Sometimes its very necessary to do sorting of a collection or integer array. The code below sorts an integer array in descending order. We only need to use the descending keyword with the orderby clause.

Static void Main(string[] args)
{

    int
[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = from n in numbers

    where n==0

    select n;

 

    Console.WriteLine("Select particular item from list");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

        Console.ReadLine();

}


following example to sort integer array in ascending order, use ascending keyword for that.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = from n in numbers

        orderby n descending

        select n;

 

    Console.WriteLine("Sort integer array in descending order");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

        Console.ReadLine();
}


The code below will show how to display a maximum of 3 items from an integer array. The process is very simple; at first arrange the list in descending order, then pick the first 3 elements from it using the Take() function.

static void Main(string[] args)
{

    int
[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

    orderby n ascending

    select n);

 

    Console.WriteLine("Sort integer array in ascending order");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

        

     }

         Console.ReadLine();

}


The following example shows how to find the second highest number from the array. The process is very simple; just arrange the array in descending order, then take the top two using the Take(n) function and use the Skip(n) function to skip the first item. And hence we can get the second highest number .

static void Main(string[] args)
{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                  orderby n descending

                  select n).Take(3);

 

    Console.WriteLine("Sort integer array in descending order");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

    Console.ReadLine();

}

How to make the sum of all numbers of an integer array? The code below shows that. Just use the Sum() function and it is done.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                  orderby n descending

                  select n).Take(2).Skip(1);

 

    Console.WriteLine("Find Second highest number from LIST using LINQ");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

    Console.ReadLine();

}

If we want to show the sum of only the even numbers then we can use the Sum() function with even selection criteria.

static void Main(string[] args)
 

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                   where(n % 2 == 0)

                   select n).Sum();

 

    Console.WriteLine("Make sum of all even number");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

The same is true for selecting the sum of all odd numbers in an integer array. Use the Sum() function with odd number selection criteria.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                   where(n % 2 != 0)

                  select n).Sum();

 

    Console.WriteLine("Make sum of all even number");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

If it is necessry to count the number of items in an array then the code below is for that. Use the Count() function with all the item selection criteria.
 

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                  select n).Count();

 

    Console.WriteLine("Count number of item in Array");

    Console.WriteLine(lowNums);

   

    Console.ReadLine();

}

The code below is for displaying the average of all numbers from an integer array. Just use the Average() function with all selection criteria.
 

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 };

    var lowNums = (from n in numbers

                  select n).Average();

 

    Console.WriteLine("Make average of all item in Array");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

We can show all distinct items from a list using the Distinct() function. Use the Distinct() function with all selection criteria of the list.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 ,5,1};

    var lowNums = (from n in numbers

                  select n).Distinct();

 

    Console.WriteLine("Select distinct item in Array");

    foreach (var x in lowNums)

    {

        Console.WriteLine(x);

    }

    Console.ReadLine();

}

We can pick the nth item from an integer array using LINQ . It's just like picking an element of an array using an index. We need to use the ElementAt(n) function to point to the nth element.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 ,5,1};

    var lowNums = (from n in numbers

                   select n).ElementAt(2);

 

    Console.WriteLine("Select nth item from list");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

Using LINQ we can identify the source data type. Use the GetType() function to do that.
 

Static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 ,5,1};

    var lowNums = (from n in numbers

                   select n).GetType();

 

    Console.WriteLine("Get type of collection");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}

Sometimes it's very necessary to find the maximum number of an array, The good news is that LINQ provides the Max() function to get it done.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 ,5,1};

    var lowNums = (from n in numbers

                   select n).Max();

 

    Console.WriteLine("Select miximum item from list");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}


Like Max you can use the Min() function to find the minimum item from a list.

static void Main(string[] args)

{

    int[] numbers = { 5, 4, 1, 3, 9, 8, 6, 7, 2, 0 ,5,1};

    var lowNums = (from n in numbers

                   select n).Min();

 

    Console.WriteLine("Select minimum item from list");

    Console.WriteLine(lowNums);

    Console.ReadLine();

}