Easy String Interpolation in C# 6.0

Content

As we all know Microsoft has launched a new version of C# called C# 6.0 with Visual Studio Ultimate 2015 Preview and there is a new feature in C# 6.0 that is based on "String interpolation".

This feature allows us to eliminate the use of "string.Format()" or formatted syntax where we can replace each format item in a specified string with the text equivalent of a corresponding object's value like:

string.Format("{0} {1}",arg0, arg1);

Console.WriteLine("{0} {1}",arg0, arg1);

Let's first see the old feature.

I am using Visual Studio Ultimate 2015 Preview.

Open Visual Studio 2015 and select "File" -> "New" -> "Project" and fill in the project name such as "Console Application1".

After creating the project, I will access some common static methods in "program.cs" without the help of a class name every time.

Now I will write some code that will print the string value in a formatted way.

Code

class Program
{
static void Main(string[] args)
{
string FirstName = "Rahul";
string LastName = "Bansal";
string PrintString = string.Format("My First Name is {0}
Last Name is {1}",FirstName, LastName);
Console.WriteLine(PrintString);
Console.ReadKey();
}
}

Note: Here I am creating a formatted string using "string.Format()" that will replace each format item in the specified string on the basis of object sequence.

string Format

Output:

Output

But in C# 6.0, we can get the same result without using "string.Format()" more easily where we can put the object in the string directly.

Syntax: "\{arg0}"

class Program
{
static void Main(string[] args)
{
string FirstName = "Rahul";
string LastName = "Bansal";
string PrintString = "My First Name is \{FirstName} and Last Name is \{LastName}";
Console.WriteLine(PrintString);
Console.ReadKey();
}
}

That will provide the same result.

Output

result

Conclusion

Now you understand the new feature of C# 6.0 that allows the use of "String interpolation" in an easy way.