Alphabet Pattern 'U' in PythonSourabh Somani11yPublished Nov 2, 2015, 12:00 AMUpdated Nov 2, 2015, 2:14 AM9.1k03Reactions×25BlogCode:str=""; for Row in range(0,7): for Col in range(0,7): if (((Col == 1 or Col == 5) and Row != 6) or (Row == 6 and Col > 1 and Col < 5)): str=str+"*" else: str=str+" " str=str+"\n" print(str); Output: CommentsJoin the conversation! Your thoughts help the community grow.Sign in to leave a commentIt is the same account you read, post and publish with — and you will come straight back to this page.Sign inCreate an account
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