Alphabet Pattern 'Y' in Python
Code:
- str="";
- for Row in range(0,7):
- for Col in range(0,7):
- if (((Col == 1 or Col == 5) and Row < 2) or Row == Col and Col > 0 and Col < 4 or (Col == 4 and Row == 2) or ((Col == 3) and Row > 3)):
- str=str+"*"
- else:
- str=str+" "
- str=str+"\n"
- print(str);
Output: