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How to Use OpenFile Dialog and Copy that Path

Munesh Sharma

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Step 1: Form

Drag down a button and write its text as "Open".

Step 2: Code

Double click on the button and write this code.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Text;

using System.Windows.Forms;

using System.Data.SqlClient;

namespace First_Csharp_app

{

public partial class Form1 : Form

{

public Form1()

{

InitializeComponent();

}

private void Button1_click(object sender, EventArgs e)

{

OpenFileDialog openfile = new OpenFileDialog();

if (openfile.ShowDialog() == System.Window.Forms.DialogResult.OK)

{

string strfilename = openfile.FileName;

MessageBox.show(strfilename);

}

Step 3: Output

Now run your application.

To learn more, you can go to my blog_munesh.