How to Use OpenFile Dialog and Copy that Path

Step 1: Form

Drag down a button and write its text as "Open".

Step 2: Code

Double click on the button and write this code.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Text;

using System.Windows.Forms;

using System.Data.SqlClient;


namespace First_Csharp_app


    public partial class Form1 : Form


        public Form1()





        private void Button1_click(object sender, EventArgs e)


            OpenFileDialog openfile = new OpenFileDialog();

            if (openfile.ShowDialog() == System.Window.Forms.DialogResult.OK)


                string strfilename = openfile.FileName;






Step 3: Output

Now run your application.

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