To Retrieve Node Value using HtmlAgilityPack with help of XPath

To Retrieve Node Value using HtmlAgilityPack with help of XPath

HTML Node Value using XPath

 

XPath, the XML Path Language, is a query language for selecting nodes from an XML document. The given below code illustrates to extract XPath using HtmlAgilityPack and webclient on the fly.

 

You need to add the reference of HtmlAgilityPack, I've used version 1.4.0.1.

You can refer http://htmlagilitypack.codeplex.com/releases/view/44954 to download the .dll

 

 

 

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using HtmlAgilityPack;

using System.Net;

using System.IO;

 

namespace DescendantUsingXPath

{

   public static class Program

    {

        static void Main(string[] args)

        {

            //WebClient object

            WebClient x = new WebClient();

 

            //Convert given url data to bytearray using DownloadData()

            byte[] byteArray = x.DownloadData(new Uri("http://stackoverflow.com/questions/1711421/lazy-stream-for-c-sharp-net?rq=1"));

 

            //Convert Byte Array into Stram

            Stream stream = new MemoryStream(byteArray);

 

            //Create new object of HtmlAgilityPack.HtmlDocument

            HtmlAgilityPack.HtmlDocument htmlDoc = new HtmlAgilityPack.HtmlDocument();

           

            //To load stream into html object

           

            htmlDoc.Load(stream);

 

            //To get the value from Given XPath

            HtmlNode node = htmlDoc.DocumentNode.SelectSingleNode(@"/html/body/div[4]/div[2]/div/div/h1/a");

 

            string strValue = node.InnerText;

 

           

 

Output 

  

 

Source: The given below URL is being pass into DownloadData() method

 

http://stackoverflow.com/questions/1711421/lazy-stream-for-c-sharp-net?rq=1