array comparison in C language ?

my question is simple but i know to do this in other way :) but need to fallow what to be done rather not required for anyone what i done altough o/p is achieved ..

Here is my question

Write a function with the function prototype of

int compare(double a[], double b[], int npts);

It will compare values in two arrays of the same size. If the corresponding values in each element of the

two arrays are the same, the function returns 1. Otherwise, it returns 0. Test the function with function calls

compare(a, a, 4) and compare(a, b, 4) with the arrays a = [1, 2, 3, 4], b = [1, 3, 4, 5].

I have directly wrote like this

#include

void main()
int result ;

{

int a[] = { 1, 1, 3, 4 };

int b[] = { 1, 2, 3, 3 };

int i;

for (i = 0; i < 4; i++)

{

if (a[i] != b[i])

{
printf(" 0 ");

}

else

{
printf(" 1 ");
}

}
}

So please help me to restart and re-build the program acc to requirement

Cheers thanks

1 Reply

Know the answer? Post it — somebody with the same question will find it here.

Vulpes13y ago
Accepted answer
This is how I'd do it:

#include

int compare(double a[], double b[], int npts);

void print_result(char a, char b, int same);

void main()
{
int result;
double a[] = { 1, 2, 3, 4 };
double b[] = { 1, 3, 4, 5 };
print_result('a', 'a', compare(a, a, 4));
print_result('a', 'b', compare(a, b, 4));
}

int compare(double a[], double b[], int npts)
{
int i ;

for(i = 0; i < npts; i++)
{
if (a[i] != b[i]) return 0;
}

return 1;
}

void print_result(char a, char b, int same)
{
if(same)
{
printf("%c and %c are the same\n", a, b);
}
else
{
printf("%c and %c are not the same\n", a, b);
}
}

The output is:

a and a are the same
a and b are not the same