Convert code to C#

Farhan Shariff

I want to change this code to C# code here val is a double value

function round7(val)
define v1,v2
v1=val
if abs(v1)>0
v2=int(log(abs(v1)))
v1=v1/(10^v2)
v1=round(v1,6)
v1=v1*10^v2
end if
return v1
end function

11 Replies

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Vulpes12y ago
Accepted answer
Hmm, the problem there is that when you round to 6 d.p. both the max and min are zero.

So, I think you do need to work to significant figures rather than decimal places. Try instead:

public static double Round7(double val)
{
double v1, v2;
v1 = val;
if(Math.Abs(v1) > 0)
{
v2 = (int)(Math.Log10(Math.Abs(v1)));
v1 = v1 / Math.Pow(10, v2);
v1 = Math.Round(v1, 6);
v1 = v1 * Math.Pow(10, v2);
}
return v1;
}

// current method code

minxv = Round7(minxv);
maxxv = Round7(maxxv);
double change = Round7((maxxv - minxv)/5);
maxxv = minxv + change * 5;
chart1.ChartAreas[0].AxisX.Minimum = minxv;
chart1.ChartAreas[0].AxisX.Maximum = maxxv;
Farhan Shariff12y ago
:)) Perfect work fine Now Thank you Sir
Farhan Shariff12y ago
It is working fine for few columns and not working for few

for instance :

Before using the code

http://i.imgur.com/qJXgYEG.png

After using the code

http://i.imgur.com/dlZ6Ech.png

Anyways I will use this
Output from this is Acceptable
Thanks once again
public static double Round7(double val)
{
double v1, v2;
v1 = val;
if(Math.Abs(v1) > 0)
{
v2 = (int)(Math.Log10(Math.Abs(v1)));
v1 = v1 / Math.Pow(10, v2);
v1 = Math.Round(v1, 6);
v1 = v1 * Math.Pow(10, v2);
}
return v1;
}
Vulpes12y ago
Try replacing the last part of that with:

minxv = Math.Round(minxv, 6);
maxxv = Math.Round(maxxv, 6);
double change = Math.Round((maxxv - minxv)/5, 6);
maxxv = minxv + change * 5;
chart1.ChartAreas[0].AxisX.Minimum = minxv;
chart1.ChartAreas[0].AxisX.Maximum = maxxv;
Farhan Shariff12y ago
for (int g1 = 0; g1 < delta_table.Columns.Count - 2; g1++)
{

string colx = delta_table.Columns[g1].ToString();

string minx = delta_table.Rows[0][colx].ToString();

int maxat = delta_table.Rows.Count-1;
string maxx = delta_table.Rows[maxat][colx].ToString();

double lower = double.Parse(table1.Rows[g1]["Delta_Lower_Limit"].ToString());
double upper = double.Parse(table1.Rows[g1]["Delta_Upper_Limit"].ToString());

double v1_lower, v2_lower;

v1_lower = lower;
if (Math.Abs(v1_lower) > 0)
{
v2_lower = (int)(Math.Log10(Math.Abs(v1_lower)));
v1_lower = v1_lower / Math.Pow(10, v2_lower);
v1_lower = Math.Round(v1_lower, 6);
v1_lower = v1_lower * Math.Pow(10, v2_lower);

}

double v1_upper, v2_upper;

v1_upper = upper;
if (Math.Abs(v1_upper) > 0)
{
v2_upper = (int)(Math.Log10(Math.Abs(v1_upper)));
v1_upper = v1_upper / Math.Pow(10, v2_upper);
v1_upper = Math.Round(v1_upper, 6);
v1_upper = v1_upper * Math.Pow(10, v2_upper);

}

double minxv = Convert.ToDouble(minx) + 2*lower;
double maxxv = Convert.ToDouble(maxx) + 2*upper;

v1 = minxv;
if (Math.Abs(v1) > 0)
{
v2 = (int)(Math.Log10(Math.Abs(v1)));
v1 = v1 / Math.Pow(10, v2);
v1 = Math.Round(v1, 6);
v1= v1*Math.Pow(10,v2);

}

double v1_1, v2_1;
v1_1 = maxxv;
if (Math.Abs(v1_1) > 0)
{
v2_1 = (int)(Math.Log10(Math.Abs(v1_1)));
v1_1 = v1_1 / Math.Pow(10, v2_1);
v1_1 = Math.Round(v1_1, 6);
v1_1 = v1_1 * Math.Pow(10, v2_1);

}

chart1.ChartAreas[0].AxisX.Minimum = v1;
chart1.ChartAreas[0].AxisX.Maximum = v1_1;

}
Vulpes12y ago
What code are you using now?
Farhan Shariff12y ago
How to do it for all the values in the x axis and not just Minimum (first) and Maximum(last)
Vulpes12y ago
You can round to 6 decimal places in C# with Math.Round(val, 6).
Farhan Shariff12y ago
I am trying to clear X axis value round the number of decimal places to 6

I thought If I set Min and Max values of the x axis it should work

but only first value that is Minimum is rounded off to 6 places but rest are not
http://i.imgur.com/6Q3PgbE.png
Vulpes12y ago
I've just tried a few examples and I think the log function must be base 10 rather than base e as the function appears to be rounding to 7 significant figures. So I'd use this instead:

public static double Round7(double val)
{
double v1, v2;
v1 = val;
if(Math.Abs(v1) > 0)
{
v2 = (int)(Math.Log10(Math.Abs(v1)));
v1 = v1 / Math.Pow(10, v2);
v1 = Math.Round(v1, 6);
v1 = v1 * Math.Pow(10, v2);
}
return v1;
}
Vulpes12y ago
I'm not sure what language that function is written in but try this:

public static double Round7(double val)
{
double v1, v2;
v1 = val;
if(Math.Abs(v1) > 0)
{
v2 = (int)(Math.Log(Math.Abs(v1)));
v1 = v1 / Math.Pow(10, v2);
v1 = Math.Round(v1, 6);
v1 = v1 * Math.Pow(10, v2);
}
return v1;
}

I've assumed that the log function is base e rather than base 10.