error - The resource cannot be found. MVC

Abhilash J A

9y15.8k.NET

Hi,

I am working on MVC 5, there is Controller: LoginUser and ActionName: Login . But showing error. 'The resource cannot be found.' How can I solve this?

Note: But when I hit break point to the Login method, then It hitting there. But suddenly the error message showing.

Please help me...

Error,

This is the ajax call to controller action method. I using usermange.js file for implimenting java script.

$('#frmSubmitLoginUser').submit(function () {
debugger;
if ($(this).valid()) {
var formData = new FormData(this);
var options = { "backdrop": "static", keyboard: true };
$.ajax({
url: "/LoginUser/Login",
type: "POST",
data: $('form').serialize(),
success: function (result) {
$('#alertMsgModalContent').html(result);
$('#alertMsgModal').modal(options);
$('#alertMsgModal').modal('show');
},
error: function (result) {
}
});
e.preventDefault();
$("#closbtn").click(function () {
$('#alertMsgModal').modal('hide');
});
}
return false;
});

View,

@using (Html.BeginForm(null, null, FormMethod.Post,new { id = "frmSubmitLoginUser" }))
{
/*Here, html another controls*/
<input type="submit" value="Submit" class="btn reg-btn btn-block">
}

Controller,

[HttpPost]
public ActionResult Login(PartnerVM partnerVM)
{
/*Save action*/
return PartialView("~/views/UserRegister/_savedSuccessMessageBox.cshtml");
}

9 Replies

Know the answer? Post it — somebody with the same question will find it here.

Abdussami Khan9y ago
Accepted answer
What I understood that you have a form and you are submitting it through Ajax.
It is because when you click on submit button and it finds that controller and action which you have provided are null and you have written click event for that button in javascript too.
So by default both clicks are being called from which ajax works and your breakpoint hits too but other route which is null not found to server.

Solution
Prevent post of submit button (in javascript) and then perform your ajax or other operation;
$('#frmSubmitLoginUser').submit(function (e) {

e.preventDefault();

//Your logic
});
Vaibhav Deshmukh9y ago
@ Abhilash Check your proper file path as well as spelling of each word in a path...!
Just Check once..
and Try @Ramesh's solution may be thats work..
Ramesh Palanivel9y ago
Hi Abilash,

Try this changes and let me know if you have any issues in that
//In HTML

<input type="button"  value="Submit" onclick="SubmitForm()" class="btn reg-btn btn-block">
In Script Write Like that,
function SubmitForm()
{
var formData = new FormData(this);
        var options = { "backdrop": "static", keyboard: true };
        $.ajax({
            url: "/LoginUser/Login",
            type: "POST",
            data: $('form').serialize(),
            success: function (result) {

                $('#alertMsgModalContent').html(result);
                $('#alertMsgModal').modal(options);
                $('#alertMsgModal').modal('show');
            },
            error: function (result) {

            }
        });
        e.preventDefault();
        $("#closbtn").click(function () {
            $('#alertMsgModal').modal('hide');
        });
}
Abhilash J A9y ago
@Remesh,

I think, there is need Ajax call, because after submit form data I want to show partialview looking like Popup window page as showing successfull message.
$('#alertMsgModalContent').html(result);
                $('#alertMsgModal').modal(options);
                $('#alertMsgModal').modal('show');
Ramesh Palanivel9y ago
Hi Abilash,

DO you really want to call ajax in submit function ?

Can I tell other way to do that?
Abhilash J A9y ago
@Remesh,

Still the error happening.

I did write this,
<form id="frmSubmitLoginUser" method="post">

/*Other html controls*/


form>
Ramesh Palanivel9y ago
HI Abilash,

Remove the HTML.Beginform and try again!..
Abhilash J A9y ago
@Vaibhav Deshmukh,

The ''_savedSuccessMessageBox' partial view is just showing Viewbag result.
ViewBag.MsgBasicUser = "Login Successfull.";
But, what is error cause ? How can I solve this issue?
Vaibhav Deshmukh9y ago
Hi Abhilash ,
Have you tried
return PartialView("~/views/UserRegister/_savedSuccessMessageBox.cshtml",model);
Bold part may be missed.. in your case
check partial view is strongly typed or not..and assign as per model in return PartialView();