Link to a form

Soumya Surendran

hai...Plz help me..........
I am creating my application using MDI form...I want to go to another form when a button clicks and the new form should be displayed in that mdi form..

5 Replies

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Kirtan Patel17y ago
Accepted answer
then Write Code in Agent Form's Load Event like below

private void Agent_Load(object sender, EventArgs e)
        {
            //Create Instance of Another Form Say Form 2
             Form2 f2 = new Form2();

            //Set MDI parent as Form1 ( Here Form1 is Main MDI Form)
             f2.MdiParent = Application.OpenForms["Form1"];

            //Show the Form
             f2.Show();
        }
Soumya Surendran17y ago
Thanks a lot.............
Soumya Surendran17y ago
thank you for your reply.....I have opened the form1 using the following code
agent ag = new agent();
ag.MdiParent = this;
menuStrip1.Enabled = false;
ag.Show();

from this form "agent" i want to go to form2 which should be displayed as the child of mdi form.....
Kirtan Patel17y ago
Hi , you can Do it this way :)

private void button1_Click(object sender, EventArgs e)
        {
            //Create Instance of Another Form Say Form 2
            Form2 f2 = new Form2();

            //Set MDI parent as Current Form
            f2.MdiParent = this;

            //Show the Form
            f2.Show();

        }
Niradhip Chakraborty17y ago
say you want to open childform(frmUsers ) from MDI from. private void mnuUsers_Click(object sender, System.EventArgs e) { foreach (Form frmuser in this.MdiChildren) { if (frmuser is frmUsers) { frmuser.Show(); frmuser.Focus(); return; } } frmUsers frmuser1 = new frmUsers(); this.AddOwnedForm(frmuser1); frmuser1.MdiParent = this; frmuser1.Show(); }