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Return a random value

Sandeep Prasad

Build a piece of code in c# language : (method/function) Which returns a random value between 1 & 6 except those numbers which are passed at the time of calling.

Just as . . .

//Definition

Private int rdm (int [] ) {

return int }

//calling

rdm(new int {3,5} )

//output 4 Or 2 Or 6 Or 1

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

siddhartha sharna8y ago
private static int rdm(int[] x)
{
int y= new Random().Next(1, 6);
int result = 0;
if (x.Contains(y))
{
return rdm(x);
}
else
{
result= y;
}
return result;
}
Sandeep Prasad8y ago
I got it .

private int rdm(int[] except)
{
var source = new List() { 1, 2, 3, 4, 5, 6 };
var i = new Random().Next(source.Count - except.Count());
var result = source.Except(except).Skip(i).First();
return result;
}