Sort Out List Box by Modified Date.

Feroz Khan

11y1.9kVisual Basic .NET

in below file is showing from a directroy file but not sort out I need sort out by modified date.

please help me about this... thanks.

private void Receipts_Load(object sender, EventArgs e)
{
try
{
string[] files = Directory.GetFiles(path);
foreach (string file in files)
{
show_receipts_listbox.Items.Add(Path.GetFileName(file));
}
}
catch(Exception ex)
{
MessageBox.Show(ex.Message, "Error");
}
}

13 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes11y ago
Accepted answer
In that case, you'll need to sort them 'manually'.

Try this:

private void Receipts_Load(object sender, EventArgs e)
{
try
{
DirectoryInfo di = new DirectoryInfo(path);
FileInfo[] fia = di.GetFiles();
FileInfo t = null;

for (int p = 0; p <= fia.Length - 2; p++)
{
for (int i = 0; i <= fia.Length - 2; i++)
{
if (fia[i].LastWriteTime > fia[i + 1].LastWriteTime)
{
t = fia[i + 1];
fia[i + 1] = fia[i];
fia[i] = t;
}
}
}

foreach (FileInfo fi in fia)
{
show_receipts_listbox.Items.Add(fi.Name);
}
}
catch(Exception ex)
{
MessageBox.Show(ex.Message, "Error");
}
}
Amar Srivastava9y ago
In a very simple way you can try this one also..

like
private void Receipts_Load(object sender, EventArgs e)
{
      try
      {
            string[] files = Directory.GetFiles(path);

            foreach (string file in files)
            {
                  show_receipts_listbox.Items.Add(Path.GetFileName(file));
            }

          //Adding an extra line here.
var sortedReceiptList = show_receipts_listbox.OrderBy(x=>x.ModifiedDate);
      }
      catch(Exception ex)
      {
            MessageBox.Show(ex.Message, "Error");
      }
}
Feroz Khan11y ago
i show in list box .txt file through directory in below image i mark in yellow that is date .txt file i want to search with this date.. so please help me about this issue. thanks..
Feroz Khan11y ago
Ok boss sort out field is not working in .net 2.0 but must i need in 2.0 ok leave it about this
now i want search field how can i search listbox value with textbox........
Vulpes11y ago
I've no idea what can be wrong with that (it works fine in .NET 4.0) but, rather than waste time trying to find out, I'd just use the code in my third post which sorts the array 'in place' and should certainly work in .NET 2.0.
Feroz Khan11y ago
Now see below error showing..
Vulpes11y ago
Yes, but the OP wants the files sorting by date last modified.

You can still do it with Array.Sort if you code a custom IComparer first. I think this should still work for .NET 2.0:

using System.Collections.Generic;

// ...

class FileInfoComparer : IComparer
{
public int Compare(FileInfo fi1, FileInfo fi2)
{
if (fi1.LastWriteTime < fi2.LastWriteTime)
return -1;
else if (fi1.LastWriteTime < fi2.LastWriteTime)
return 1;
else
return 0;
}
}

// ...

private void Receipts_Load(object sender, EventArgs e)
{
try
{
DirectoryInfo di = new DirectoryInfo(path);
FileInfo[] fia = di.GetFiles();
Array.Sort(fia, new FileInfoComparer());

foreach (FileInfo fi in fia)
{
show_receipts_listbox.Items.Add(fi.Name);
}
}
catch(Exception ex)
{
MessageBox.Show(ex.Message, "Error");
}
}
Jignesh Trivedi11y ago
Hi,
using Array.sort method, you can sort the array...
string[] files = Directory.GetFiles(path);
Array.Sort(files);
hope this will help you.
Feroz Khan11y ago
Please tell me any other procedure because i am using .Net 2.0
Vulpes11y ago
To use the OrderBy() extension method, you need to include the following using directive near the top of your file:

using System.Linq;

You also need to be using .NET 3.5 (VS 2008) or later.
Feroz Khan11y ago
Please see showing below error
orderBY not accepting..
Feroz Khan11y ago
in OrderBy showing error ...
Vulpes11y ago
Try this:

private void Receipts_Load(object sender, EventArgs e)
{
try
{
DirectoryInfo di = new DirectoryInfo(path);
string[] files = di.GetFiles()
.OrderBy(fi => fi.LastWriteTime)
.Select(fi => fi.FullName)
.ToArray();

foreach (string file in files)
{
show_receipts_listbox.Items.Add(Path.GetFileName(file));
}
}
catch(Exception ex)
{
MessageBox.Show(ex.Message, "Error");
}
}