Introduction

When I started learning SQL, I found out several issues, which I thought would be interesting to share. For our needs, let us use AdventureWorks2012 database, which can be obtained here.

Don't Forget about NULL

Let's have a look at the following query,

select Count(*) from Sales.SalesOrderDetail

The result will be,

Some Common Mistakes When Querying SQL Database

Filtering by CarrierTrackingNumber,

select Count(*)
from Sales.SalesOrderDetail
Where CarrierTrackingNumber = '4911-403C-98'

will give us,

It is natural to assume that the result of the following query,

select Count(*)
from Sales.SalesOrderDetail
Where CarrierTrackingNumber <> '4911-403C-98'

would be 121317-12=121205. However, in fact, it is,

So where are all the other rows? Those rows have NULL in CarrierTrackingNumber column.

The fact is that comparison between NULL and the value ('4911-403C-98' in our case) will return UNKNOWN, while WHERE clause returns only statements that are true. Comparison between value and NULL will also give UNKNOWN, which is shown on a screenshot below.

So if you need to compare your value and NULL, you should use operator IS NULL. For example,

select Count(*)
from Sales.SalesOrderDetail
Where CarrierTrackingNumber <> '4911-403C-98' or CarrierTrackingNumber IS NUll

will give us expected,

INNER JOIN is Not a Golden Hammer

Let us select all job candidates and id of their addresses (it is more natural to select addresses but let us not complicate the query for our learning needs). As this information is situated in 2 different tables linked by the column BusinessEntityId, a common practice for the beginners is to use INNER JOIN on this column.

select C.JobCandidateID, A.AddressID
from HumanResources.JobCandidate C inner join Person.BusinessEntityAddress A
on c.BusinessEntityID = A.BusinessEntityID

Two candidates are selected,

Everything looks fine until we realize that there are 13 job candidates in the first table.

Again, the problem is NULL. If we examine JobCandidate table closely, we'll see that the column BusinessEntityId can take NULL as its values.

Therefore, if we want to select all job candidates, we should use LEFT JOIN instead of INNER JOIN, which will just select all rows from the left table.

select C.JobCandidateID, A.AddressID
from HumanResources.JobCandidate C left join Person.BusinessEntityAddress A
on c.BusinessEntityID = A.BusinessEntityID

And voila!

If Syntax Construct Exists, Why Don’t You Use It?

Let us have a look at the two queries, which do exactly the same: select items, which cost more than 100 and were bought more than 1000 times.

Select t.ProductID, count(*) AS TransactionCount From Sales.SalesOrderDetail t
WHERE (Select count(*) From Sales.SalesOrderDetail t1
Where t1.ProductId = t.ProductId AND t1.UnitPrice > 100) > 1000
Group by t.ProductId
Select ProductID, count(*)
From Sales.SalesOrderDetail
Where UnitPrice > 100
Group by ProductID
Having count(*) > 1000

Which one to use? Here are the statistics,

As you can see, the first one is imperformant. Therefore, if subquery or join can be replaced by a more simple approach, you should better to do so.

Conclusion

This is by no means an exhaustive list of common pitfalls but still, I hope the article was useful to you.

6 Comments

Join the conversation! Your thoughts help the community grow.

Hadshana Kamalanathan7y ago
Nice explained
- Bohdan Stupak7y ago
  Thanks. I'm glad you've enjoyed it.
C# Corner7y ago
Very well written, it would be great if you could continue the session.
- Bohdan Stupak7y ago
  Thanks. I'll do my best to see if I can proceed with another findings
Rushi Mehta7y ago
Nicely explained the join concept
- Bohdan Stupak7y ago
  Thank you for you kind words