Add multiple values in List

Udit Chauhan

8y18.1kLearn iOS Programming

is it possible to add below in list in c#?

5 Replies

Know the answer? Post it — somebody with the same question will find it here.

Sreekanth Reddy8y ago
@Suraj Kumar

Good thought...
Will it work as per expected ?
Suraj Kumar8y ago
try this,
//EmployeeId,EmployeeName,EmplCode
            List<string[]> EmpDtls = new List<string[]>();
            string[] empDtl1 = new string[] { "101", "A", "EMP001" };
            string[] empDtl2 = new string[] { "102", "B", "EMP002" };
            string[] empDtl3 = new string[] { "103", "C", "EMP003" };

            EmpDtls.Add(empDtl1);
            EmpDtls.Add(empDtl2);
            EmpDtls.Add(empDtl3);

            //Remember array element is accessed by name not index
Susanta Rout8y ago
create a class with properties EmployeeId,EmployeeName,EmplCode

public class Employee
{
public int EmployeeId{get,set}
   public string EmployeeName{get,set}
   public string EmplCode{get,set}
}

List Emplst=new  List();

EmployeeList emp=new  EmployeeList();
emp. EmployeeId=123;
emp. EmployeeName="Ram";
emp. EmplCode="abc"
Emplst.Add(emp);

using a class you can add but directly you add only one value

if you want directly
List Emplst=new List();
string EmployeeName="Ram";
Emplst.Add(EmployeeName);
Munish Kumar8y ago
Hope this would help..

Create a class Employee
public class Employee
{
    public string EmployeeID;
    public string EmployeeCode;
    public string EmployeeName;
}
and, then create list of this class containing objects of the same like below..
List emp = new List() {
            new Employee { EmployeeID = "1", EmployeeCode = "101",
EmployeeName = "A" }
        };

        Console.WriteLine(emp[0].EmployeeID);
        Console.WriteLine(emp[0].EmployeeCode);
        Console.WriteLine(emp[0].EmployeeName);
Sreekanth Reddy8y ago
It is not possible with List.
& ofcourse we are having Dictionary or Hashtable where :
one argument as KEY
another arguament as VALUE
But in your case its like being single object split as argument.
For example in feature one more property added like EMPSALARY, Then your expectaion would be like another argument which leads to re-modify(Not a generic).
Better try to utilize the list itself...

List obj = new List< Employee>
Now access like below :

foreach(var a in obj)
{
//Access the values... Not matter how many properties even in future...
}