API Return response

Question

Hi Below response is returned by API . I want to display Error message . I am using Asp.net Web Based Applcation C#. {'status':false,'message':'Pickup Address is required
Pickup State is required
The Pickup Pincode field must be exactly 6 characters in length.
'} If status is O.K then successful message should be displayed Thanks

Amit Mohanty · Answer

Check this var client = new RestClient("your url"); client.Timeout = -1; var request = new RestRequest(Method.GET); request.AddHeader("content-type", "application/json"); var response = client.Execute(request); if (response.IsSuccessful) { var dDynamic = JsonConvert.DeserializeObject (response.Content); if(dDynamic["status"]) Console.WriteLine(string.Format("Success : {0}", dDynamic["message"].ToString())); else Console.WriteLine(string.Format("Failure : {0}", dDynamic["message"].ToString())); } else { // to do code after get error Console.WriteLine(string.Format("Failed. Code : {0}", response.StatusCode)); }

Pasang Tamang · Answer

Hi, Using Newtonsoft.Json, you should be able to achieve what you want. Please check below code for example public class ResponseModel { [JsonPropertyName("status")] public bool Status { get; set; } [JsonPropertyName("message")] public string Message { get; set; } } var response = "{"status":false,"message":"Pickup Address is required\nPickup State is required\nThe Pickup Pincode field must be exactly 6 characters in length.\n"}"; var responseContent = JsonConvert.DeserializeObject (response); if (responseContent.Status == false) { var message = responseContent.Message; } Regards, Pasang

Naimish Makwana · Answer

Please refer below code. Create a class to parse your Response. public class Response { [JsonPropertyName("status")] public bool Status { get; set; } [JsonPropertyName("message")] public string Message { get; set; } } Code to Get data from URL and parse it to valid data formate. string requestURL = "Your GET API URL"; //EX: https://test.api.com/api/users string urlParameters = "Your Query string parameters"; //EX: ?user_id=10 Or string.Empty using (var client = new HttpClient()) { client.BaseAddress = new Uri(requestURL); // Add an Accept header for JSON format. client.DefaultRequestHeaders.Accept.Add( new MediaTypeWithQualityHeaderValue("application/json")); // Get response from requested URL var response = client.GetAsync(urlParameters).Result; //If request is success if (response.IsSuccessStatusCode) { //var sampleResponse = response.Content.ReadAsStringAsync().Result; var sampleResponse = "{"status":false,"message":"Pickup Address is required\nPickup State is required\nThe Pickup Pincode field must be exactly 6 characters in length.\n"}"; var responseContent = JsonConvert.DeserializeObject (sampleResponse); if (responseContent.Status) { Console.WriteLine("Successful responses received"); } else { Console.WriteLine($"Error from responses {responseContent.Message}"); } } } Please let me know in case of any issue. Thanks :)

Vishal Joshi · Answer

Hello You can try the below code for GET requests. static async Task GetProductAsync(string path) { Product product = null; HttpResponseMessage response = await client.GetAsync(path); if (response.IsSuccessStatusCode) { product = await response.Content.ReadAsAsync (); } return product; } Thanks

Ramco Ramco · Answer

Hi Amit I am getting error IsSucessful response doed not exist in the current context Thanks

API Return response

Answers (5)