c# logical programs

Question

Write a program to display the series[2,15,41,80,132,197………] in windows form application?

Sachin Singh · Answer

The reasoning is like this 2 + 13*1 = 15 15 + (13 * 2) = 41 41 + (13 * 3) = 80 80 + (13 * 4) = 132 132 + (13 * 5) = 197. so logic should be res=(seed+(13*i)) seed=res; cw(res) public void yourMethod() { int n= Convert.ToInt32(txtLenghth.Text); // a textbox in winform int seed=2; int res=0; List int > series= new List int >(){seed}; for ( int i=0;i { res=(seed+(13*i)) seed=res; series.Add(res); } var commaSeparated=string.Join int >( ", " , series); txtSeries.Text=commaSeparated; // another textbox to display }

Muhammad Imran Ansari · Answer

You can also write your custom code in you windows form like: public static string getSeries( int startVal, int diff, int NthVal) { string series = "[" + startVal; int prevVal = startVal; for ( int i = 0; i { if (i > 0) { prevVal = prevVal + (diff * i); series += ", " + prevVal; } } series += "]" ; return series; } Call your method in your class as: string series = getSeries(2, 13, 6);

Rajanikant Hawaldar · Answer

Found it on internet, you can implement it using winform as you wish using System; class GFG{ static void printSeries( int N) { int ith_term = 0; // Generate the ith term and for ( int i = 1; i { ith_term = (13 * i * (i - 1)) / 2 + 2; Console.Write(ith_term + ", " ); } } // Driver Code public static void Main(String[] args) { int N = 7; printSeries(N); } }

Jaydeep Patil · Answer

void Number Series( int N) { int ith_term = 0; for ( int i = 1; i ith_term = (13 * i * (i - 1)) / 2 + 2; cout ", " ; } }

Vishal Yelve · Answer

using System; class Program { static void Main() { int a = 2, total = 9; for ( int i = 1; i Console.Write(a + " " ); a += 13 * i; } } } /* run: 2 15 41 80 132 197 275 366 470 */

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