compare 2 keys to get value

Thanks very much. ur coding is very helpful.
Once again, I am very grateful to you.

i see. May i know how to change it?

richTextBox4.Clear();
            string AssR = output.Replace("->", " ");
            richTextBox4.AppendText(AssR);

            String[] split = (output).Split(new string[] { "\r\n\t", "->" }, StringSplitOptions.RemoveEmptyEntries);
            string[] split2 = new string[split.Length];
            for (int i = 0; i < split.Length; i++)
            {
                split2[i] = split[i];
                richTextBox4.AppendText(split2[i].ToString() + "\r\n");
            }


            foreach (String sort2 in richTextBox4.Lines)
            {
                if (!(sortList2.ContainsKey(sort2)))
                {
                    sortList2.Add(sort2, 1);
                }
            }

            ArrayList arryKey = new ArrayList();
            foreach (string key in arryKey)
            {
                if (sortList.ContainsKey(key))
                {
                    if (!sortList2.ContainsKey(key)) sortList2.Add(key, sortList[key]);
                }
            }
            string text ="";
            foreach (string key in sortList2.Keys)
            {
                text += String.Format("{0}:{1}\r\n", key, sortList2[key]);
            }
            richTextBox5.Clear();
            richTextBox5.AppendText(text); 
       

may i know that My code have something error?

Well, you've evidently changed the lists again but even so you should be getting both the key and the correct value (not 1).

Are you sure you've copied the code correctly and haven't inadvertently altered something?

the output is show below, but not i wan the values.
1 2:1
2 1:1
1:1
2:1
1 3:1
2 3:1
1 2 3:1
3 1:1
3 2:1
1 3 2:1
2 3 1:1
3:1
 

for example 1 2 in arrayList is same key with  1 2 in sortedLIst. therefore the value should be 3.
e.g. 1 2:3
 how i get and display the value?

The code should be displaying the key/value pairs in the RichTextBox.

Is there some other value you want to display?

thanks for ur help. ur code is very helpful.
 may i know how to get and display the value?

OK, try this instead:

actually in my arrayList has duplicate keys which shown below:
1 2
1 3
2 1
2 3
1 2 3
3 1
3 2
1 3 2
2 3 1
1
2
1
3
2
1
2
3
1 2
3
3
1
3
2
1 3
2
2 3
1
 but in my sortedList just has
1: 4
2: 4
1 2: 3
3:  4
1 3: 3
2 3: 3
1 2 3: 2

if the keys in the arrayList are same with sortedList key, then will come out the value.

i had try ur code, the error is show that the same keys has been added.
  ArrayList arryKey = new ArrayList();
           
            string text = "";
            foreach (String key1 in sortList2.Keys)
            {

                arryKey.Add(key1);
                foreach (string key in arryKey)
                {
                    if (sortList.ContainsKey(key))
                    {
                        sortList2.Add(key, sortList[key]);
                        text += String.Format("{0}:{1}\r\n", key, sortList2[key]);
                    }
                }

                richTextBox5.AppendText(text);

            }
 

Well, the code definitely works because I tested it before posting (except I used a MessageBox rather than a RichTextBox) and it produces PRECISELY your expected output. 

I don't understand the error you're getting unless you're using different data to that shown above and trying to add the same key more than once to a SortedList which isn't allowed.

i already try ur code, but got error. cant show the same keys and values.

I'd do it something like this (I've included code to load the lists which I needed for testing purposes):

      string[] strings = 
      {
        "1",
        "2",
        "3",
        "1 2",
        "1 3",
        "3 1",
        "2 3",
        "1 2 3",
        "2 3 1"
      };
      ArrayList arryKey = new ArrayList(strings);
      SortedList sortList = new SortedList();
      sortList.Add("1", 4); 
      sortList.Add("2", 4); 
      sortList.Add("3", 4); 
      sortList.Add("1 2", 3); 
      sortList.Add("1 3", 3); 
      sortList.Add("2 3", 4); 
      sortList.Add("1 2 3", 4); 
      sortList.Add("2 3 1", 4); 
      SortedList sortList2 = new SortedList();


      string text = "";


      foreach(string key in arryKey)
      {
         if(sortList.ContainsKey(key))
         {  
           sortList2.Add(key, sortList[key]);
           text += String.Format("{0}:{1}\r\n", key, sortList2[key]);
         }  
      }
     
       richTextBox5.AppendText(text);