@foreach (var item in Model) {

Zafar Iqbal

10y15.8k.NET

Server Error in '/' Application.

Object reference not set to an instance of an object.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.NullReferenceException: Object reference not set to an instance of an object.

Source Error:

Line 28: Line 29: @foreach (var item in Model) { Line 30: Line 31:

Line 27:

Please Help me out in this

18 Replies

Know the answer? Post it — somebody with the same question will find it here.

Dorababu Meka10y ago
Accepted answer
Can you change your return view as follows return View(employees);
Ateeq Atiq Ali Khan6y ago
put the entire code in if loop @if(Model!=null){foreach (var item in Model)}
Amit Kumar10y ago
Hi dear,

Firstly check the model count if model count then bind
use code like..

@if (Model.Count != 0)
{
//Write your code here.......
}
Zafar Iqbal10y ago
Thank you so much sir for your efforts you put in solving my problem .I got my issue resolved
Ranjit Powar10y ago
Change your action as

namespace MVCDemo.Controllers
{
public class EmployeeController : Controller
{
// GET: Employee
public ActionResult Index()
{
EmployeeBusinessLayer employeeBusinessLayer = new EmployeeBusinessLayer();
List employees = employeeBusinessLayer.Employees.ToList();
return View(employees );
}
}
}
Zafar Iqbal10y ago
Sir i am uploading the source code also and here the controller also on this view in which i am getting the error you please help me out in this case

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using BusinessLayer;
namespace MVCDemo.Controllers
{
public class EmployeeController : Controller
{
// GET: Employee
public ActionResult Index()
{
EmployeeBusinessLayer employeeBusinessLayer = new EmployeeBusinessLayer();
List employees = employeeBusinessLayer.Employees.ToList();
return View();
}
}
}
Dorababu Meka10y ago
This is how your controller should be

[HttpGet]
public ActionResult Index()
{
var employees= new List(); //Model
employees.Add(new Employee {
Name = "XYZ",
Gender = "Male });

employee.Add(new Employee {
Name = "ABC",
Gender = "Male });

return View(employees);
}
Dorababu Meka10y ago
You are showing the Model but not the controller you are binding. Can you post your controller code that you are binding to the view
Zafar Iqbal10y ago
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace BusinessLayer { public class Employee { public int ID { get; set; } public string Name { get; set; } public string Gender { get; set; } public string City { get; set; } public DateTime DateOfBirth { get; set; } } }
Zafar Iqbal10y ago
Done it also but still the same error msg
Ranjit Powar10y ago
In action method create list of employee as

Listlst=new List
Add employees in lst and then return from view

return View(lst);;

On View

@model List
Dorababu Meka10y ago
Does your BusinessLayer.Employee is returning list of employees? can you show us your controller code
Zafar Iqbal10y ago
Still not working as i have bind also

Zafar Iqbal10y ago

@model IEnumerable @{ ViewBag.Title = "Index"; }

Index

@Html.ActionLink("Create New","Create")

If ( Model != null ) { @foreach (var item in Model) { } }

@Html.DisplayNameFor(model =>model.Name)	@Html.DisplayNameFor(model => model.Gender)	@Html.DisplayNameFor(model => model.City)	@Html.DisplayNameFor(model => model.DateOfBirth)
@Html.DisplayFor(modelItem => item.Name)	@Html.DisplayFor(modelItem => item.Gender)	@Html.DisplayFor(modelItem => item.City)	@Html.DisplayFor(modelItem => item.DateOfBirth)	@Html.ActionLink("Edit", "Edit", new { id=item.ID }) \| @Html.ActionLink("Details", "Details", new { id=item.ID }) \| @Html.ActionLink("Delete", "Delete", new { id=item.ID })

Ranjit Powar10y ago
How do you pass list of model?
Dorababu Meka10y ago
Can you share the screen shot of your Model, if your model is null then you should have a condition check like

@if (Model!=null)
{
// bind your table here
}
Zafar Iqbal10y ago
No Sir , holding data check whether it is null but how i can do it.?
Dorababu Meka10y ago
Does ur model is holding data check whether it is null