generating numbers in sequence

cheguri saikumar

I want to generate numbers automatically in sequence that is from 1 to 100 in c# windows application can any one help me how to generate numbers.

Thanks,

saikumar

15 Replies

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Suraj Kumar7y ago
You can try this
int[] noOfSeries = Enumerable.Range(1, 100).ToArray();
Hope this will help you.
cheguri saikumar7y ago
namespace DocSort_CPA.Forms
{
public partial class TicketScreen : Form
{
public TicketScreen()
{
InitializeComponent();
}
public int ticketNo = 0;
public string orderedTicketNum = string.Empty;
private void btnSubmit_Click_1(object sender, EventArgs e)
{

{
string From = string.Empty;
string FromPWD = string.Empty;
string ToAddress = string.Empty;
string BCCAddress = string.Empty;
string Name = string.Empty;
string Phone = string.Empty;
string Email = string.Empty;
string Comments = string.Empty;
string ticket = string.Empty;
string MessageBody = string.Empty;
try
{
ConfirmLicenseManager objConfirmLicenseManager = new ConfirmLicenseManager();
DocSortResult getAllConfigValues = objConfirmLicenseManager.GetAllConfigValues();
if (getAllConfigValues.resultDS != null && getAllConfigValues.resultDS.Tables[0].Rows.Count > 0)
{
foreach (DataRow dr in getAllConfigValues.resultDS.Tables[0].Rows)
{
switch (Convert.ToString(dr["Config_Name"].ToString()).ToUpper())
{
case "FROMEMAIL":
From = (this.Decrypt(dr["Config_Value"].ToString()));
break;
case "FROMPASSWORD":
FromPWD = (this.Decrypt(dr["Config_Value"].ToString()));
break;
case "TOADDRESS":
ToAddress = dr["Config_Value"].ToString();
break;
case "BCCADDRESS":
BCCAddress = dr["Config_Value"].ToString();
break;
}
}
}
{
txtticket.Text = ticketNo.ToString();
ticketNo = Convert.ToInt32(txtticket.Text)+1;
MessageBox.Show("Your ticket has been created." ,ticketNo.ToString());
txtticket.Text = ticketNo.ToString();

orderedTicketNum = orderedTicketNum + ",";
}
Jaish Mathews7y ago
I love algorithms and any custom logics better to have in a separate class like below.
Whenever you need, you call as Sequence.Next. This starts from 1 and up to 100, then again start from 1. You can change the logic in below class itself.
static class Sequence
{
        private static int _value = 0;
        private static readonly object m_lock = new object();

        public static int Next
        {
            get
            {
                lock (m_lock)
                {
                    if (_value == 100)
                        _value = 0;
                    return ++_value;
                }
            }
        }
    }
Sreekanth Reddy7y ago
Try This please :

namespace yourapp : Form
{
public int ticketNo =0;
public string orderedTicketNum = string.Empty;
private void button1_Click(object sender, System.EventArgs e)
{
txtticket.Text = ticketNo.ToString();
}
private void button1_Click(object sender, System.EventArgs e)
{
ticketNo = Convert.ToInt32(txtticket.Text)+ 1;
MessageBox.Show("Your ticket has been created." ticketNo.ToString());
txtticket.Text = ticketNo.ToString();
orderedTicketNum = orderedTicketNum+",";
}
}
Sreekanth Reddy7y ago
This helps you to get the ordered ticket Numbers separated by comma into a separate string "orderedTicketNum":

namespace yourapp : Form
{
public int ticketNo =1;
public string orderedTicketNum = "1";
private void button1_Click(object sender, System.EventArgs e)
{

}
private void button1_Click(object sender, System.EventArgs e)
{

MessageBox.Show("Your ticket has been created." ticketNo.ToString());

txtticket.Text = ticketNo.ToString();
ticketNo = ticketNo + 1;
orderedTicketNum = orderedTicketNum+",";
}
}

Mark it as answer, If it helps else come with query.
Thank you.
cheguri saikumar7y ago
Thanks it is working but the thing is Iam unbale to generate numbers in order

Thanks,
Sreekanth Reddy7y ago
If you want to generate numbers in random dont use "Random" class.
Because "Random" class is used to a random value witin specified range.
Directly do with For loop which I had provided in my previous answers.
namespace yourapp : Form
{
public int ticketNo =1;
private void button1_Click(object sender, System.EventArgs e)
{

}
private void button1_Click(object sender, System.EventArgs e)
{

MessageBox.Show("Your ticket has been created." ticketNo.ToString());

txtticket.Text = ticketNo.ToString();
ticketNo = ticketNo + 1;
}
}
Sanwar Ranwa7y ago
Hello cheguri

Please check these Links

https://www.youtube.com/watch?v=gog3_xnf86M

https://www.youtube.com/watch?v=QnbIfuQV8S4

https://www.codeproject.com/Questions/550351/HowplustoplusGenerateplusAuto-Incrementplusplusnum

https://stackoverflow.com/questions/26931528/random-number-generator-with-no-duplicates
cheguri saikumar7y ago
I want to generate numbers automatically and put those numbers in textbox control.
For example i have generated random numbers but i am unable to generate numbers in ascending order

here is my random number generator code

Random r = new Random();
int i;
i = r.Next(1, 100);
MessageBox.Show("Your ticket has been created"., ,i.ToString());
txtticket.Text = i.ToString();

But i want to generate as 1,2,3....98,99,100.
Sreekanth Reddy7y ago
This works for your requirement :

private void button1_Click(object sender, System.EventArgs e)
{
// On load of form displaying 0 in textbox
txtnum.Text = "0";
}
private void button1_Click(object sender, System.EventArgs e)
{
//Get the value from the text box
int num = Convert.Toint32(txtnum.Text);

txtnum.Text = num.ToString();
}

Mark it as answer, If it helps. Else come up with next query.
cheguri saikumar7y ago
Can you please send me the full code i am new to .net c#.

Thanks,
Sreekanth Reddy7y ago
Then the logic is like I stated in my previous answer :

for(int i =1; i< =100; i++)
{
// "i" contains number. It loops upto 100
}
cheguri saikumar7y ago
I want to print in text box control for example when i click ok button it has to show 1 and again when i click on ok button it has to show 2 and so on....

Thanks,
cheguri saikumar7y ago
I dont want to print just i want to generate numbers
Sreekanth Reddy7y ago
Where you needs to print in windows application(on which control) ?

Any how the logic is :

for(int i=0; i<100 ; i++)
{

}