Help removing unwanted decimal places ???

Waqas Ali

Hello,
This is my code

decimal averagePrice = (decimal)dvdDS.Tables["manager"].Compute("Avg(Price)", "");

textBox3.Text = Convert.ToString(averagePrice);

I want the textbox to display "averagePrice" upto 3 decimal places.
eg I get: 6.66666666666666666
I want: 6.666

Any help would be appreciated
Thank You

4 Replies

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Santhosh Kumar Jayaraman14y ago
Accepted answer
textBox3.Text = averagePrice.ToString("###,###.000");
Jignesh Trivedi14y ago
hi,

i think you can not get your required out put directly but
try

double ff = 6.6666666666666666;
double gg = Math.Floor(ff);
double newff = gg + (Math.Floor((ff - gg) * 1000) / 1000);

it gave me out put 6.666.

hope this will help you.
Vulpes14y ago
If you always want to round to the lower third decimal place (i.e. 6.666 rather than 6.667) then use this instead:

textBox3.Text = (Decimal.Truncate(averagePrice * 1000m)/ 1000m).ToString("F3");
Gohil Jayendrasinh14y ago
// just two decimal places
String.Format("{0:0.00}", 123.4567); // "123.46"
String.Format("{0:0.00}", 123.4); // "123.40"
String.Format("{0:0.00}", 123.0); // "123.00"

// max. two decimal places
String.Format("{0:0.##}", 123.4567); // "123.46"
String.Format("{0:0.##}", 123.4); // "123.4"
String.Format("{0:0.##}", 123.0); // "123"

// at least two digits before decimal point
String.Format("{0:00.0}", 123.4567); // "123.5"
String.Format("{0:00.0}", 23.4567); // "23.5"
String.Format("{0:00.0}", 3.4567); // "03.5"
String.Format("{0:00.0}", -3.4567); // "-03.5"