How can I read an Xml Document in listBox control in C#..?

Ankit Rathore

Hi Guys,

I have one XML document and I wanted to show the xml data in listBox.
So what will be the approach for that ?
Please Help...

4 Replies

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Kirtan Patel17y ago
Accepted answer
Hi Ankit,

Here is your Answer

please check "do you like this answer" check box it helps me :)
private void btnLoadXML_Click(object sender, EventArgs e)
{
    string path_of_xml = "XMLFile.xml";
    XmlDocument doc = new XmlDocument();
    doc.Load(path_of_xml);
    listBox1.Items.Clear();
    foreach (XmlNode node in doc.ChildNodes)
    {
        if (node.Name == "Authors")
        {
            foreach (XmlNode node_of_node in node.ChildNodes)
            {
                if (node_of_node.Name == "Author")
                {
                    string firstname = node_of_node["FirstName"].InnerText;
                    string lastname = node_of_node["LastName"].InnerText;
                    listBox1.Items.Add(firstname + " " + lastname);
                }
            }
        }
    }
}
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Birendra Kumar5y ago
using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.IO;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

using System.Xml;

//-------------------------------------

private void button1_Click(object sender, EventArgs e)

{

string path_of_xml = @"C:\Users\Text2.xml";

XmlDocument doc = new XmlDocument();

doc.Load(path_of_xml);

listBox1.Items.Clear();

foreach (XmlNode node in doc.ChildNodes)

{

if (node.Name == "Root")

{

foreach (XmlNode node_of_node in node.ChildNodes)

{

if (node_of_node.Name == "Message")

{

foreach(XmlNode node_node_of_node in node_of_node.ChildNodes )

{

if(node_node_of_node.Name == "Body")

{

string b1 = node_node_of_node["B1"].InnerText;

string b2 = node_node_of_node["B2"].InnerText;

listBox1.Items.Add(b1 + " " + b2 );

}

}

}

}

}

}

}

//----------------------------------------------------------

// -----Text2.xml-----

SIZE 101.6 mm, 25.4 mm

DIRECTION 0,0

TEXT 703,107,"ROMAN.TTF",180,1,12,"10040"

BARCODE 753,130,"128M",18,0,180,3,6,"10040"

PRINT 1,1

SIZE 101.6 mm, 25.4 mm

DIRECTION 0,0

TEXT 703,107,"ROMAN.TTF",180,1,12,"10040"

BARCODE 753,130,"128M",18,0,180,3,6,"10040"

PRINT 1,1

SIZE 101.6 mm, 25.4 mm

DIRECTION 0,0

TEXT 703,107,"ROMAN.TTF",180,1,12,"10040"

BARCODE 753,130,"128M",18,0,180,3,6,"10040"

PRINT 1,1

SIZE 101.6 mm, 25.4 mm

DIRECTION 0,0

TEXT 703,107,"ROMAN.TTF",180,1,12,"10040"

BARCODE 753,130,"128M",18,0,180,3,6,"10040"

PRINT 1,1

SIZE 101.6 mm, 25.4 mm

DIRECTION 0,0

TEXT 703,107,"ROMAN.TTF",180,1,12,"10040"

BARCODE 753,130,"128M",18,0,180,3,6,"10040"

PRINT 1,1

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Ankit Rathore17y ago
Suppose I have an xml file like:-
<Authors>
<Author>
<FirstName>JohnFirstName>
<LastName>DoeLastName>
Author>
<Author>
<FirstName>JaneFirstName>
<LastName>EodLastName>
Author>
Authors>

now in my listbox I wanted to show First name and last name of Author :\

+1
Lalit M17y ago
try this code sample the code snippet uses a XMLTextReader object to read from an XML file. Each document element in the XML file is then read and added as an item to the ListBox.

XmlTextReader Xreader=new XmlTextReader(HttpContext.Current.Server.MapPath("toolbox.xml"));
Xreader.WhitespaceHandling=WhitespaceHandling.None;
XmlDocument Xdoc=new XmlDocument();
Xdoc.Load(Xreader);
lst_company.Items.Add("LIST OF CONTROLS");
lst_company.Items.Add(" ");
lst_company.Items.Add(" ");
XmlNode Xnode=Xdoc.DocumentElement;
AddText(Xnode,1);

    private void AddText(XmlNode Xnode, Int32 intlevel)
    {
        XmlNode Xnodeworking;
        String strindent = new string(' ', 2 * intlevel);
        string strvalue = (string)Xnode.Value;
        if (strvalue != null)
        {
            strvalue = " : " + strvalue;
        }
       if (Xnode.NodeType == XmlNodeType.Element)
            {
                XmlNamedNodeMap mapattributes = Xnode.Attributes;
                foreach (XmlNode xnodattribute in mapattributes)
                {
                    lst_company.Items.Add(strindent + " " + xnodattribute.Name + ":" + xnodattribute.Value);
                        lst_company.Items.Add(" ");
                }
         if (Xnode.HasChildNodes)
        {
            Xnodeworking = Xnode.FirstChild;
            while (Xnodeworking != null)
            {
                AddText(Xnodeworking, intlevel + 1);
                Xnodeworking = Xnodeworking.NextSibling;
            }
        }
    }

more info
--------
http://www.java2s.com/Code/CSharp/GUI-Windows-Form/FillXMLdatatoListBox.htm
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