how can splite ()

Najim Mulla

C:\Abc\file.text
how can splite ("\")
to get only file name as like file.text

6 Replies

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Kunal Vaishya11y ago
        protected void Page_Load(object sender, EventArgs e)
        {

            string sFile = GetFileNameWithExt(@"C:\Abc\file.text");
        }

        public string GetFileNameWithExt(String strFilePath)
        {
            string[] FileStpit1 = strFilePath.Split(Convert.ToChar(@"\"));
            string sFileName = FileStpit1[Length - 1];

            return sFileName;
        }
Kunal Vaishya11y ago
Hi , Using Split function you can do manually using below code.

Example:

         protected void Page_Load(object sender, EventArgs e)
        {

            string sFile = GetFileNameWithExt(@"C:\Abc\file.text");
        }

        public string GetFileNameWithExt(String strFilePath)
        {
            string[] FileStpit1 = strFilePath.Split(Convert.ToChar(@"\"));
            string sFileName = FileStpit1[Length - 1];

            return sFileName;
        }
Khargesh Rajput11y ago
string text = @"C:\Abc\file.text";
string myString = (text.Length > 8) ? text.Substring(text.Length - 9, 9) : text;

Response.Write(myString);

you can get directory name like

string filePath = @"C:\Abc\file.text";

string directoryName;

directoryName = Path.GetDirectoryName(filePath);

    Console.WriteLine("GetDirectoryName('{0}') returns '{1}'",

        filePath, directoryName);

    filePath = directoryName;

string fileName = @"C:\Abc\file.text";

string path = @"C:\Abc\";

string result;

result = Path.GetFileNameWithoutExtension(fileName);

Console.WriteLine("GetFileNameWithoutExtension('{0}') returns '{1}'",

    fileName, result);

result = Path.GetFileName(path);

Console.WriteLine("GetFileName('{0}') returns '{1}'",

    path, result);