How to Double check locking in Singleton Design pattern

//thread-safety using double-check locking public sealed class Singleton {private static Singleton instance = null;private static readonly object padlock = new object();Singleton(){}public static Singleton Instance{get{if (instance == null){lock (padlock){if (instance == null){instance = new Singleton();}}}return instance;}} }

public class DoubleCheckLocking {

    public static class SearchBox {
        private static volatile SearchBox searchBox;

        // private constructor
        private SearchBox() {}

        // static method to get instance
        public static SearchBox getInstance() {
            if (searchBox == null) { // first time lock
                synchronized (SearchBox.class) {
                    if (searchBox == null) {  // second time lock
                        searchBox = new SearchBox();
                    }
                }
            }
            return searchBox;
        }
}

Obtaining lock on the SearchBox.class, only one thread will enter the synchronized block at a time. So the first thread enters then finds searchBox is null and creates it and then leaves the synchronized block, then the second thread enter the block then it finds that the searchBox is not null because the first thread already created it so it will not create a new instance of searchBox.

The double checked pattern is used to avoid obtaining the lock every time the code is executed. If the call are not happening together then the first condition will fail and the code execution will not execute the locking thus saving resources.

2 Replies

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Amit Kumar4y ago

Accepted answer

Hi ,

Check this code

Uday Dodiya4y ago
```
public class DoubleCheckLocking {

    public static class SearchBox {
        private static volatile SearchBox searchBox;

        // private constructor
        private SearchBox() {}

        // static method to get instance
        public static SearchBox getInstance() {
            if (searchBox == null) { // first time lock
                synchronized (SearchBox.class) {
                    if (searchBox == null) {  // second time lock
                        searchBox = new SearchBox();
                    }
                }
            }
            return searchBox;
        }
}
```
Obtaining lock on the SearchBox.class, only one thread will enter the synchronized block at a time. So the first thread enters then finds searchBox is null and creates it and then leaves the synchronized block, then the second thread enter the block then it finds that the searchBox is not null because the first thread already created it so it will not create a new instance of searchBox.

The double checked pattern is used to avoid obtaining the lock every time the code is executed. If the call are not happening together then the first condition will fail and the code execution will not execute the locking thus saving resources.
+1