How to pass model and id using ajax call

Aghil Varghese

11y1.3kAJAX

How to get the data using ajax call containing model and rowFeeId together in controller.when i am using this function i am getting the model but the rowFeeId is null.

Ajaxcall

function DeleteFee(_this) {

var par = $(_this).closest('tr');

var rowFeeId = par.find('.RowFeeId').val();
$.ajax({
url: '@Url.Action("DeleteInvoiceFee", "Invoice")',
dataType: "Html",
type: "POST",
traditional: true,
data:{ 'RowFeeId': rowFeeId, 'model': $('#FormSubmitInvoice').serialize() },
success: function (result) {
// alert(result);
$('#addFeedetailsSection').html(result);
},
error: function (xhr) {
alert('error');
}
//dataType :
})

}

controller

public ActionResult DeleteInvoiceFee(InvoiceViewModel model,string RowFeeId)
{
................
}

2 Replies

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Shuvojit Halder11y ago
My suggestion is that you should check step by step, means

use

var par = $(_this).closest('tr');
alert(par );
var rowFeeId = par.find('.RowFeeId').val();
alert(rowFeeId );

if it shows undefined then do,

var par = $(e).closest('tr');
0
Manas Mohapatra11y ago
Hi,

As per your code your want to return HTML content from controller.
So please use below code:
public ActionResult DeleteInvoiceFee(InvoiceViewModel model, string RowFeeId)
{
   // Create your HTML string
   string html = "
";
   html += "