How to permutation and combination?

Ken H

14y3.1k

hi,
   i have 8 digital,now I want to know a choice 5 combination how many kinds of.

Code fragment:

#include
void main()
{
int ResultNum[8]={1,8,9,10,11,14,17,20},i,j=0,k=0;
for (i=0;i<8;i++)
{
  for (j=i+1;j<8;j++)
  {

      if(k<=5)
   {
         // how to do?
      printf("\n");
       k++;
   }
   else if (k>=5) k=0;
  }

}
}

Below is the result of simulation:
NO.1:
        1,8,9,10,11
NO.2:
         1,8,9,10,14
NO.3:
          1,8,9,10,17
NO.4:
          1,8,9,10,20
NO.5:
           1,8,9,11,14
NO.6:
           1,8,9,11,17
NO.7:
            1,8,9,11,20
NO.8:
           1,8,10,11,14
......
......
......

thanks.

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes14y ago
Accepted answer
Try:

#include "stdio.h"

void main()
{
int n[] = {1,8,9,10,11,14,17,20};
int i, j, k, l, m;
int count = 0;
for(i = 0; i < 8; i++)
for(j = i +1; j < 8; j++)
for(k = j + 1; k < 8; k++)
for(l = k + 1; l < 8; l++)
for(m = l + 1; m < 8; m++)
{
count++;
printf("NO.%d:\n ", count);
printf("%d,%d,%d,%d,%d\n", n[i], n[j], n[k], n[l], n[m]);
}
}
0
Ken H14y ago
Hi Vulpes,
You are very good.

thank very much.
0
Scott14y ago
Check out
http://www.codeproject.com/Articles/26050/Permutations-Combinations-and-Variations-using-C-G
0