How to sort XML file... using XSL ???

Hi, XSL file for transform XML to XML with sorting is below. .. I think the process of transformation using C# is clear .. using System; using System.IO; using System.Xml; using System.Xml.XPath; using System.Xml.Xsl; public class Sample { private const String filename = "data.xml"; private const String stylesheet = "sort.xsl"; public static void Main() { XslTransform xslt = new XslTransform(); xslt.Load(stylesheet); XPathDocument xpathdocument = new XPathDocument(filename); XmlTextWriter writer = new XmlTextWriter(Console.Out); writer.Formatting=Formatting.Indented; xslt.Transform(xpathdocument, null, writer, null); System.Console.ReadLine(); } }

Your file isn't well formed so I repaired it. (data.xml) 02/04/2005 17:21 xxxxxxx 04/04/2005 09:12 yyyyyyy 01/04/2005 12:46 zzzzzzzz and file sort.xsl

Date	Title	Time	Descritpion

if you change "date" in for "title" data will be sorted using value of title :) Place both files into the same directory and open data.xml in IE to see result. Good tool for work with XM? files is Altova XMLspy www.altova.com Tutorial about XML/XSL is here http://www.w3schools.com/xml/default.asp By.