How to use binary operation

Jonathan Crispe

I was able to convert Hex values to binary,
but i can't figure out how to calculate the 2 16bit-binary value: An example shown below.

public partial class Form1 : Form
{
uint byhex1 = 0;
uint byhex2 = 0;

public Form1()
{
InitializeComponent();

}
private void Form1_Load(object sender, EventArgs e)
{

}
private void BTN_operation_Click(object sender, EventArgs e)
{
if (RB_andgate.Checked)
{
BTN_operation.Text = "&";
byhex1 = Convert.ToUInt16(TXB_hexvalue1.Text, 16);
LBL_binary1.Text = Convert.ToString(byhex1, 2).PadLeft(16, '0');
byhex2 = Convert.ToUInt16(TXB_hexvalue2.Text, 16);
LBL_binary2.Text = Convert.ToString(byhex2, 2).PadLeft(16, '0');
LBL_totalhex.Text = "0 X " + (byhex1 & byhex2).ToString("X4");
}
if (RB_orgate.Checked)
{
BTN_operation.Text = "|";
byhex1 = Convert.ToUInt32(TXB_hexvalue1.Text, 16);
LBL_binary1.Text = Convert.ToString(byhex1, 2).PadLeft(16, '0');
byhex2 = Convert.ToUInt32(TXB_hexvalue2.Text, 16);
LBL_binary2.Text = Convert.ToString(byhex2, 2).PadLeft(16, '0');
LBL_totalhex.Text = "0 X " + (byhex1 | byhex2).ToString("X4");
}
if (RB_xorgate.Checked)
{
BTN_operation.Text = "^";
byhex1 = Convert.ToUInt32(TXB_hexvalue1.Text, 16);
LBL_binary1.Text = Convert.ToString(byhex1, 2).PadLeft(16, '0');
byhex2 = Convert.ToUInt32(TXB_hexvalue2.Text, 16);
LBL_binary2.Text = Convert.ToString(byhex2, 2).PadLeft(16, '0');
LBL_totalhex.Text = "0 X " + (byhex1 ^ byhex2).ToString("X4");
}
}
}
how to put an exception just like in picture below in my code?

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes15y ago
Accepted answer
Try the following:

private void BTN_operation_Click(object sender, EventArgs e)
{
try
{
byhex1 = Convert.ToUInt16(TXB_hexvalue1.Text, 16);
byhex2 = Convert.ToUInt16(TXB_hexvalue2.Text, 16);
}
catch(Exception ex)
{
MesssageBox.Show("An illegal operand was entered.", "Word Binary Calculator");
return;
}

LBL_binary1.Text = Convert.ToString(byhex1, 2).PadLeft(16, '0');
LBL_binary2.Text = Convert.ToString(byhex2, 2).PadLeft(16, '0');

if (RB_andgate.Checked)
{
BTN_operation.Text = "&";
LBL_totalhex.Text = "0 X " + (byhex1 & byhex2).ToString("X4");
}
else if (RB_orgate.Checked)
{
BTN_operation.Text = "|";
LBL_totalhex.Text = "0 X " + (byhex1 | byhex2).ToString("X4");
}
else if (RB_xorgate.Checked)
{
BTN_operation.Text = "^";
LBL_totalhex.Text = "0 X " + (byhex1 ^ byhex2).ToString("X4");
}
}
Hemant Kumar15y ago
There is no need to code tons of codes, loops, to convert hex to binary string. Convert.ToInt32 function is very useful for this purpose.
Let's convert the "A" character to binary format.
```
private string hex2binary(string hexvalue)
{
  string binaryval = "";
  binaryval = Convert.ToString(Convert.ToInt32(hexvalue, 16), 2);
  return binaryval;
}
```
When we call hex2binary("A"); it will return "1010" similar samples below;

hex2binary("1a"); will return "11010";
hex2bianry("1a2c"); will return "1101000101100"; and so on.

Keep in mind that this hex to binary conversion style uses 32 bit integer number.