How to write this program by using C++

Md Nayeem

8y1.1k

Read the input numbers were given in a file and find out the maximum number, minimum number and the sum of those input numbers were given in that file as output by using C++ Programming.(File Input and Output).

5 Replies

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Mahesh Verma8y ago
Accepted answer
Hi Md Nayeem,

Sorry, actually I didn't check my output.

Please remove max and min from for loop, initialize it with first element of an array before loop. Please have a look into this screenshot, you will find your all answer :-
#include
#include

using namespace std;

int main()
{
    ifstream f("hello.txt");
    int num,i=0,max,min,sum=0;
    int arr[10];

    while(!f.eof()){
        f>>num;
        arr[i]=num;
        i++;
    }
    max=arr[0];     //assume first number is the maximum number;
    min=arr[0];     //assume first number is the minimum number;
    cout<<"File data :- ";
    for(i=0;i<=9;i++){
        cout<<"\t"<
        if(max//to find max number
           max=arr[i];
        if(min>arr[i])       //// to find min number
           min=arr[i];

        sum=sum+arr[i];
    }

    cout<<"\n\n Maximum number :- "<
    cout<<"\n\n Minimum number :- "<
    cout<<"\n\nSum of all number :- "<
      return 0;
}
Md Nayeem8y ago
Mahesh Verma in your program you took input as 12 23 44 55 36 47 58 29 10 15 in hello.txt

but in the output you show maximum number 15 as maximum number but in this case maximum number is 58.So how can i solve this program error.Thanks in advance .
Mohan Arumugam8y ago
1. #include
2. using namespace std;
3. int main()
4. {
5. int n, reversedNumber = 0, remainder;
6. cout << "Enter an integer: ";
7. cin >> n;
8. while(n != 0)
9. {
10. remainder = n%10;
11. reversedNumber = reversedNumber*10 + remainder;
12. n /= 10;
13. }
14. cout << "Reversed Number = " << reversedNumber;
15. return 0;
16. }
Enter an integer: 12345
Reversed number = 54321

Mahesh Verma8y ago

#include
#include
using namespace std;
int main()
{
ifstream f("hello.txt");
int num,i=0,max,min,sum=0;
int arr[10]={0};
while(!f.eof()){
f>>num; //read data from file
arr[i]=num; //store into an array
i++;
}
for(i=0;i<=9;i++){
max=arr[0]; //assume first number is the max number;
min=arr[0]; //assume first number is the min number;
if(max//to find max number
max=arr[i];
if(min>arr[i]) // to find min number
min=arr[i];
sum=sum+arr[i]; //sum of all elements of a file
}
cout<<"\n Maximum number :- "<
cout<<"\n Minimum number :- "<
cout<<"\nSum of all number :- "<
return 0;
}

In my "hello.txt" file the data is :-

12 23 44 55 36 47 58 29 10 15

Now, output is :-

Rajneesh Chaubey8y ago

#include
using namespace std;
int main()
{
int i, n;
int sum=0;
float arr[100];
cout << "Enter total number of elements(1 to 100): ";
cin >> n;
cout << endl;
// Store number entered by the user
for(i = 0; i < n; ++i)
{
cout << "Enter Number " << i + 1 << " : ";
cin >> arr[i];
}
// Loop to store largest number to arr[0]
for(i = 1;i < n; ++i)
{
// Change < to > if you want to find the smallest element
if(arr[0] < arr[i])
arr[0] = arr[i];
}
cout << "Largest element = " << arr[0];
for(i = 1;i < n; ++i)
{
// Change < to > if you want to find the smallest element
if(arr[0] > arr[i])
arr[0] = arr[i];
}
cout << "Smallest element = " << arr[0];
for(i=0;i
{
sum=sum+arr[i];
}
cout << "Sum of All elements = " << sum;
return 0;
}