When I run the code, I make my second entry the same as the first, assuming the binarysearch finds the same entry in the array, I should get the message box.
The Problem is that the search dosen't find the same entry even though I have entered the same number.
public
partial class Form1 : Form{
int[] storage = new int[20];
int counter = 0;
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
//number is read from "entry"
int entry = Int32.Parse(Entry.Text); int retVal = Array.BinarySearch(storage,entry); if (retVal < 0) // add to storage if not there{
storage[counter] = entry;
counter++;
}
else // Message box{
MessageBox.Show("That entry is already listed, Please enter a different number.", "Need a new entry", MessageBoxButtons.OK);}
AlanPosted May 6, 2008, 5:00 PM
The Array.BinarySearch() method only works properly with sorted arrays which is not what you've got here - remember that when the 'storage' array is created all elements are set to zero. Instead, use the Array.IndexOf() method:
int
retVal = (int)Array.IndexOf(storage, entry);