Mathematical Operator in an expression

Farhad Ahmad

10y896Visual Basic .NET

I am using the expression below to calculate the distance, however the parser is unable to process this expression

Distance = (1/2) * (GRAVITATIONAL_FORCE) * (time *2)

If i use the above expression as below it works.

Distance = FRACTION * GRAVITATIONAL_FORCE * (time * 2)

FRACTION = 0.5

I have tried to assign FRACTION = (1/2), and use FRACTION as variable in above expression it does not work either.

Please suggest what is wrong with the first expression.

Also, is there a function for a square of a number? in above expression time is a variable that need to be square, I have been writing expression as (time *time) or (time * 2)

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Bikesh Srivastava10y ago
Accepted answer
Distance = ((double)1/(double)2) * (GRAVITATIONAL_FORCE) * (time *2)
+1
Tapan Patel10y ago
The reason behind is when you say 1/2, compiler tries for the operation considering the return value to be assigned will be of type integer and hence 1/2 results in 0 as they are of type ints .
In order to correct it you can either cast 1 to double and 2 to double and then use it like
Distance = ((double)1/(double)2) * (GRAVITATIONAL_FORCE) * (time *2)
or just cast your constants to double data types by
Distance = (1.0/2.0) * (GRAVITATIONAL_FORCE) * (time *2)
Please mark it as answer if it addresses the issue.
0
Midhun Tp10y ago
Hi,

Please try below code-
Distance = (1.0/2.0) * (GRAVITATIONAL_FORCE) * Math.Pow(time,2)
0