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my jquery function is called two times what is that problem

Koteswararao Mallisetti

16y4k

$('.dlImgs').mouseover(function(e) {
             alert('d');
             return;
         });
it is write in $(document).ready function
this is my code but it display alerts two time what is the problem

1 Reply

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Koteswararao Mallisetti16y ago
this is the event bubbling issue that image all are in the one datalist so the event is raised first time from the source and next time form the container control that is here datalist so two time method is calling .