Newbie : Issues with constructor chaining

Well, you can't have two constructors which have the same number of arguments of the same type.

So, you'll have to delete one of the constructors which takes one argument in order that the application can compile.

This, of course, means that only one of the fields can be initialized with the value passed to this constructor. As a result of constructor chaining the other argument will be zero.

If you want to initialize both fields with non-zero values, then you should call the constructor which takes both arguments directly i.e. no chaining is necessary.

You'll also need to make the constructors public (they're private by default) so they can be accessed by code outside the class.

The following compiles and runs OK:

using System;

class ClassName
{
      // Field data.
      public int id;
      public int age;

      // Chained constructors
      public ClassName() : this(0) {}
      public ClassName(int myID) : this(myID, 0) { }

      // Master constructor
      public ClassName(int myID, int myAge)
      {
          id = myID;
          age = myAge;
      }
}

class Test
{
   public static void Main()
   {
      ClassName myClass = new ClassName(10);
      Console.WriteLine(myClass.id); // 10 
      Console.WriteLine(myClass.age); // 0
      ClassName myClass2 = new ClassName(11, 20);
      Console.WriteLine(myClass2.id); // 11 
      Console.WriteLine(myClass2.age); // 20
      Console.ReadKey();
   }
}

Incidentally, the default value for an int field is 0 anyway so the other field will be initialized to 0 here without the need for constructor chaining.