Open file using OpenFileDialog Class

Eugene Gabriyelov

I am trying to do something very simple but am having a hard time making it work. I need to open a browse file dialog onclick of a button (windows application) and allow the user to select a file from a specified directory and open the file when onclick of the open button in the open file dialog. My code is below. For some reason it doesnt work. Please help!
private void btnHandouts_Click(object sender, EventArgs e)
{
string fileNamePath;
string fileNameOnly;
OpenFileDialog fdlg = new OpenFileDialog();
fdlg.Title = "Open File";
fdlg.InitialDirectory = @"..\Handouts";
fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
fdlg.CheckFileExists = true;
fdlg.FilterIndex = 2;
fdlg.RestoreDirectory = true;
if (fdlg.ShowDialog() == DialogResult.OK)
{
fileNamePath = fdlg.FileName;
fileNameOnly = Path.GetFileName(fileNamePath);
FileStream fileStream = new FileStream(@"..\Handouts\" + fileNameOnly, FileMode.Open);
fileStream.Close();
}
}

4 Replies

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Roei Bar17y ago

Accepted answer

if you want to just open the selected file use this

   private void btnHandouts_Click(object sender, EventArgs e)
        {
            string fileName;
            OpenFileDialog fdlg = new OpenFileDialog();
            fdlg.Title = "Open File";
            fdlg.InitialDirectory = @"..\Handouts";
            fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
            fdlg.CheckFileExists = true;
            fdlg.FilterIndex = 2;
            fdlg.RestoreDirectory = true;
            if (fdlg.ShowDialog() == DialogResult.OK)
            {
                Process.Start(fdlg.FileName);
            }
        }

Eugene Gabriyelov17y ago
This worked perfectly. Thank you very much for your help!
Eugene Gabriyelov17y ago
Thank you for your response. Unfortunately this code yeilds the same result. The file that is selected doesnt open, infact, nothing happens at all. Any other suggestions?

Roei Bar17y ago

change your code to the following

    private void btnHandouts_Click(object sender, EventArgs e)
        {
            string fileName;
            OpenFileDialog fdlg = new OpenFileDialog();
            fdlg.Title = "Open File";
            fdlg.InitialDirectory = @"..\Handouts";
            fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
            fdlg.CheckFileExists = true;
            fdlg.FilterIndex = 2;
            fdlg.RestoreDirectory = true;
            if (fdlg.ShowDialog() == DialogResult.OK)
            {
                fileName = fdlg.FileName;
                FileStream fileStream = new FileStream(fileName, FileMode.Open);
                fileStream.Close();
            }
        }

the problem was in the path you built, it wasnt necessary since

fdlg.FileName is the fileName + Extension and full path