Popup messages

If you want to display the message saying "Any user is already loggedin into the application", then you can use the below code.
//Get the current process name
Process currentProcess = Process.GetCurrentProcess();
string currProcessName = currentProcess.ProcessName;
// Get all the instances of current application
Process[] prevAppInstance = Process.GetProcessesByName(currProcessName);
if (prevAppInstance.Length > 1)
{
//Show error msg if the same exe is already running
MessageBox.Show("The application is already runninig in this machine");
return;
}
else
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}

Hi Venkat,
As you mentioned it is Windows application (desktop) not web right? Can you explain what you mean by when new user logged in it should notify with the user already loged in. How two users will execute the Windows application from single desktop, is that application is sharing some thing? Can you provide me the use case (flow), i will try to help you for sure?
You can display the popup basically it will be form with no border and you can write ESC key code and it will be close down or after few seconds we can close that form. And in that form we can display the user information.
But i am not sure what you mean by two different user using same application.
-Kapil

hello.....venk

why u are not using ASP.net default login, create new user, and user identification like controls in your project. i think it will solve ur all problems.

hi

private void button1_Click(object sender, System.EventArgs e) 
{
   Form dlg1 = new Form();
   dlg1.ShowDialog();
}
thanks

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