Return Partial views based on condition best approach.

Question

How to return partial views based on condition.

Sachin Singh · Answer

You can use dictionary to store partial views name and based on key you can return any of them. public ActionResult Edit(string Key) { Dictionary PartialViews = new Dictionary (); PartialViews.Add( "Employee" , "_PartialEmployee" ); PartialViews.Add( "Department" , "_PartialDepartment" ); PartialViews.Add( "Manager" , "_PartialManager" ); string partialViewName=PartialViews[Key]; return PartialView(partialViewName); }

Ashutosh Gupta · Answer

public ActionResult getpartialview(string action){ switch (action){ case "action" : return PartialView( "action" ); break ; case "Y" : return PartialView( "~/abc/abcd.cshtml" ); break ; default : return PartialView( "Default" ); } }

Kiran Mohanty · Answer

Hi, You can use switch case if you have 2 to 3 conditional scenario . public ActionResult Action1 ( object key ){ switch (key){ case 1: return PartialView( "Case1" ); break ; case 2: return PartialView( "~/customFolder/nonMatchingAction.cshtml" ); break ; case 3: return PartialView( "viewWithDifferentLayout" ); break ; default : return PartialView( "Default" ); } }

Return Partial views based on condition best approach.

Answers (3)