Returning

Guest User

Given the following simple code snippet

// Worker method with implementation

public int DoCalculation(int receivingInt)

int multiply = receivingInt * 3;

return multiply;

// Caller method

public void CallerMethod(Object sender, Eventargs args)

int startingInt = 10;

int gettingVariable = DoCalculation(startingInt);

textbox1.text = gettingVariable.ToString();

The worker method has a method return type and therefore returns the int multiply variable which has stored the result from calling the DoCalculation method.

Now given the below code snippet

public Product GetProduct(int productId)

string sql = "some query implementation";

object[] parms = { "@ProductId", productId };

return DB.Read(sql, parms);

Why is the return keyword returning a static DB class and static Read method rather than return the local variables?

Ive never seen anything like this in methods where the return goes off to another method altogether, away from the usual worker and caller pattern...

Any more info needed please ask...

Cheers!

2 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes14y ago
Accepted answer
There's nothing strange about this, Steven.

The return statement can be followed by any expression which evaluates to a value of the enclosing method's return type or which is implicitly convertible to its return type.

That expression may or may not include or depend upon local variables, method arguments or fields of the enclosing class or struct.

Here it must be the case that the DB.Read method returns an int so we can use the method call itself with the return statement. There is no need to assign it to a local variable first.
Sam Hobbs14y ago
Why do you say "static DB class and static Read method"? What says they are static? If they are static then it might be a bad design but otherwise it is okay.

Note that "DB.Read(sql, parms)" is an expression. A return statement uses an expression. If you have not seen return statements with expressions that are more than a single object (variable or whatever you want to call it) then it is only because you have not seen enough code. Now that you are seeing more code, you are becoming more experienced and encountering a greater variety of code.