Amount : digits to Word Convertion

Question

I need a function which accepts amount in digits as argument and returns amount in string (words). For eg. 1600 - One Thousand Six Hundred 210 - Two Hundred Ten Thanks in advance!

theLizard · Answer

Sam, yes it should be relatively easy to convert to C# but unfortunately the code I posted is not without its deficencies, there are more big names than what I have shown and the max number of digits you can enter with this code is 69 + decimal places. There are also other little things which I did not take care of.. Sam said, "What is UnicodeString? Is it sufficient to do: #define UnicodeString const wchar_t *" The UnicodeString type represents a dynamically allocated Unicode string whose maximum length is limited only by available memory. UnicodeString ~2^30 characters 4 bytes to 2GB Unicode characters, 8-bit (ANSI) characters, multi-user servers and multi-language applications in C# the string type is a string of Unicode characters. So in C# your methods would be something like string setToWords(string numberSet) Sam said, "What is TElement? I don't see it's definition, but perhaps I am just missing an #include." Yes, you are missing an #include but, TElement is a class containing a member declared as a UnicodeString (I have discarded this, not needed) Sam said, "In the constructor I assume that a, b, c and d are also called units, tens, teens and major and the names should be changed to be consistent. If not then I am not sure what they are." a,b,c,d are char arrays which are then )for simplicity and ease) loaded into vectors of TElements (now obsolete) std::vector units, ... tens, ... teens and ... mojor, names were not important for exercise, but yes you could name them to be more appropriate or even load the elements from a file if you wanted to. std::vector replaced with std::vector replacing the need to do this return(units[n-1].e); with this return(units[n-1]); string name = getUnitName("3"); string getUnitName(string unit) { int value = StrToInt(unit); //convert the string representation of the unit (number) sent "3" as integer is 3; return(units[value-1]) //reason why value-1 is used is that 0 is not represented in any of the arrays of names so first element of any array is the first name in group of names, for units, it is "one", for tens it is "ten" and so on. //return(units[3-1]) //return(units[2]) //in this case, since arrays are zerro based, the return value (in element 2) is be "three" } Here is an update of the app (no DLL involved)

Sam Hobbs · Answer

Hopefully, theLizard, it will be reasonably easy to convert the C++ code to C#. There are some things however that I do not understand about the C++ code. What is UnicodeString? Is it sufficient to do: #define UnicodeString const wchar_t * There are other things that I assume are declared in the header. What is TElement? I don't see it's definition, but perhaps I am just missing an #include. In the constructor I assume that a, b, c and d are also called units, tens, teens and major and the names should be changed to be consistent. If not then I am not sure what they are.

theLizard · Answer

Vulpes; So there's still a window of opportunity for my free version - 7 to 9 digits or 10 if you're lucky ;) Yeah, but I have given enough code for anyone to write or convert the code to their own version, can't be seen to be holding hands here is a big number ---> 6541646943516876876546516541698416446846841987164798416794167641368768765416469435168768765465165416984164468468419871647984167941676413687687.99 To words its is: Six Quinquardragintillion, Five hundred and Fourty One Quattuorquardragintillion, Six hundred and Fourty Six Trequardragintillion, Nine hundred and Fourty Three Duoquardragintillion, Five hundred and Sixteen Unquardragintillion, Eight hundred and Seventy Six Quardragintillion, Eight hundred and Seventy Six Novemtrigintillion, Five hundred and Fourty Six Octotrigintillion, Five hundred and Sixteen Septtrigintillion, Five hundred and Fourty One Sextrigintillion, Six hundred and Ninenty Eight Quintrigintillion, Four hundred and Sixteen Quattuortrigintillion, Four hundred and Fourty Six Tretrigintillion, Eight hundred and Fourty Six Googol, Eight hundred and Fourty One Duotrigintillion, Nine hundred and Eighty Seven Untrigintillion, One hundred and Sixty Four Trigintillion, Seven hundred and Ninenty Eight Novemvigintillion, Four hundred and Sixteen Octovigintillion, Seven hundred and Ninenty Four Septvigintillion, One hundred and Sixty Seven Sexvigintillion, Six hundred and Fourty One Quinvigintillion, Three hundred and Sixty Eight Quattuorvigintillion, Seven hundred and Sixty Eight Trevigintillion, Seven hundred and Sixty Five Duovigintillion, Four hundred and Sixteen Unvigintillion, Four hundred and Sixty Nine Vigintillion, Four hundred and Thirty Five Novemdecillion, One hundred and Sixty Eight Octodecillion, Seven hundred and Sixty Eight Septdecillion, Seven hundred and Sixty Five Sexdecillion, Four hundred and Sixty Five Quindecillion, One hundred and Sixty Five Quattuordecillion, Four hundred and Sixteen Tredecillion, Nine hundred and Eighty Four Duodecillion, One hundred and Sixty Four Undecillion, Four hundred and Sixty Eight Decillion, Four hundred and Sixty Eight Nonillion, Four hundred and Nineteen Octillion, Eight hundred and Seventy One Septillion, Six hundred and Fourty Seven Sexillion, Nine hundred and Eighty Four Quintillion, One hundred and Sixty Seven Quadrillion, Nine hundred and Fourty One Trillion, Six hundred and Seventy Six Billion, Four hundred and Thirteen Million, Six hundred and Eighty Seven Thousand, Six hundred and Eighty Seven Dollars and Ninety Nine Cents and there are a lot more to follow, cosmologists, eat your heart out

Vulpes · Answer

So there's still a window of opportunity for my free version - 7 to 9 digits or 10 if you're lucky ;)

theLizard · Answer

Yep, Cosmologists will love it I suppose but to make it a bit easier for some, I have created a DLL which can be called from C# code. the number that can be converted is limited to 6 digits including decimal point, to be able to use it to the Centillion value, you will need to pay a small fee (can't have everything for free, can you!) If you want to pay a little send a pm.. namespace WindowsFormsApplication1 { public partial class Form1 : Form { [DllImport(@"your path to DLL\NumToWordsDLL.dll")] // public static extern int getWords([MarshalAs(UnmanagedType.LPWStr)]string outbuf, bool isCurrency, bool wantPoint, [MarshalAs(UnmanagedType.LPWStr)]string currencyMajor, [MarshalAs(UnmanagedType.LPWStr)]string currencyMinor, bool US, [MarshalAs(UnmanagedType.LPWStr)]StringBuilder outBuff, int len); public Form1() { InitializeComponent(); } private void Form1_Load(object sender, EventArgs e) { } private void button1_Click(object sender, EventArgs e) { int len = 2048; StringBuilder outBuff = new StringBuilder(len); getWords(te.Text, chIsCurrency.Checked, chWantPoint.Checked, teMajor.Text, teMinor.Text, rbUS.Checked, outBuff, len); re.Text = outBuff.ToString(); } } }

Vulpes · Answer

Cosmologists will love that version ;) You should do an article as well, theLizard - C++ doesn't seem to get much of an airing on here.

theLizard · Answer

+ The following code will handle any number up to the Centillion value, this is a number of 10 ^303, 1 with 303 zerro's try the sample program. //--------------------------------------------------------------------------- #pragma hdrstop #include "TNumbersToWords.h" //--------------------------------------------------------------------------- __fastcall TNumToWords::TNumToWords() { int i; char *a[] = { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" }; char *b[] = { "ten", "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninenty" }; char *c[] = { "eleven", "twelve", "thirteen", "forteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" }; char *d[] = { "hundred", "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "Sextillion", "Septillion","Octillion","Nonillion","Decillion","Undecillion","Duodecillion", "Tredecillion","Quattuordecillion","Quindecillion","Sexdecillion","Septendecillion", "Octodecillion","Novemdecillion","Vigintillion","Centillion"}; for(i=0; i for(i=0; i for(i=0; i for(i=0; i } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::numberToWords(UnicodeString number, bool isCurrency, bool wantPoint, UnicodeString currencyMajor, UnicodeString currencyMinor) { int i=0; theNumber = number; curMajor = currencyMajor; curMinor = currencyMinor; wantAsCurrency = isCurrency; showPointWord = wantPoint; sets.clear(); words.clear(); getNumberSets(); if(wantAsCurrency) centPart = getCentPart() + curMinor; else centPart = getCentPart(); for(i = 0; i { words.push_back(setToWords(sets[i])); } theNumber = assembleWords(); if(wantAsCurrency) theNumber += curMajor; return(theNumber += " " + centPart); } //--------------------------------------------------------------------------- void __fastcall TNumToWords::getNumberSets() { bool hasCommas = theNumber.Pos(",") > 0? true:false; UnicodeString a, b, c, d; if(theNumber.Pos(".") > 0) b = theNumber.SubString(1, theNumber.Pos(".")-1); a = b; while(a.Length() > 3) { c = a.SubString(a.Length() -2, 3); sets.push_back(c); a = a.SubString(1, a.Length() - c.Length()); d = a.LastChar(); if(d == "," || d == " " || d == "-") a = a.SubString(1, a.Length() - 1); } if(a.Length() > 0) sets.push_back(a); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::getCentPart() { int pos = theNumber.Pos("."); int i, num; bool unitsOnly = false; UnicodeString centPart="", s=""; if(pos == 0) return("zerro cents"); s = theNumber.SubString(pos+1, theNumber.Length() - pos+1); if(s.Length() >= 3) unitsOnly = true; if(s.Length() unitsOnly = false; if(showPointWord && !wantAsCurrency) centPart = "point "; else centPart = "and "; if(unitsOnly) //deal with any point value greater than two decimal places { for(i=0; i { num = StrToInt(s[i+1]); if(num == 0) continue; centPart += units[num-1].e + " "; } } else //two dicimal places only... { for(i=0; i { num = StrToInt(s[i+1]); if(i ==0 && num != 0) { centPart += tens[num-1].e + " "; continue; } else if(num == 0) continue; centPart += units[num-1].e + " "; } } return(centPart); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::setToWords(UnicodeString numberSet) { int i =0; UnicodeString s, tmp; if(numberSet[1] == '0') numberSet = numberSet.Delete(1, 1); if(numberSet.Length() == 3) { //1st digit is hundred tmp = getHundreds(numberSet[1]) + " hundred "; numberSet = numberSet.Delete(1, 1); } if(numberSet.Length() == 2) { if(numberSet[1] != '0') { if(StrToInt(numberSet) = 9) tmp += getTeens(numberSet); else if(StrToInt(numberSet) >=20 && StrToInt(numberSet) tmp += getTens(numberSet); } else numberSet = numberSet.Delete(1,1); } if(numberSet.Length() == 1) tmp += getUnits(numberSet); return(tmp); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::getHundreds(UnicodeString unit) { int value = StrToInt(unit); return(units[value-1].e); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::getTens(UnicodeString unit) { UnicodeString s; int value = StrToInt(unit[1]); s = tens[value-1].e; value = StrToInt(unit[2]); if(value != 0) s += " " + units[value -1].e; return(s); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::getTeens(UnicodeString unit) { int value = StrToInt(unit); value -= 10; return(teens[value-1].e); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::getUnits(UnicodeString unit) { int value = StrToInt(unit); return(units[value-1].e); } //--------------------------------------------------------------------------- UnicodeString __fastcall TNumToWords::assembleWords() { int i; UnicodeString a; for(i = words.size(); i > 0; i--) { a += words[i-1] + " "; if(i > 1) a += major[i-1].e + ", "; } return(a); } //--------------------------------------------------------------------------- void __fastcall TNumToWords::getNumberNames(TListBox *lb) { for(int i=0; i lb->Items->Add(major[i].e); } //--------------------------------------------------------------------------- #pragma package(smart_init)

Vulpes · Answer

OK Suthish, I've just uploaded the article now :)

Suthish Nair · Answer

I think we don't have an article/blog about digit to number conversion tool here. It will be helpful, if you post one.

Vulpes · Answer

I can do a quick article if you like, Suthish, but I just wondered whether there was much point with so many other converters around? The only reason I posted it here was because it did exactly what the OP wanted and I haven't tried the others which Krishna linked to. Incidentally, I wrote another version for the Indian numbering system (lakhs, crores) as that was coming up a lot on the forums at the time. I can dig it out if anyone's interested.

Suthish Nair · Answer

Vulpes, Can you post this as an Article/Blog here :)

Vulpes · Answer

Here's a very simple 'number to text' converter which I wrote years back when there weren't so many others available :) It just deals with integers in the range plus or minus 2 billion (or so). However, one thing it does have is that it can display numbers in either US or UK format. In your case, answer 'n' to UK numbering to get the exact text that you want: using System; class Program { static void Main() { string input; int number; bool isValid; bool isUK = false; Console.WriteLine("
Enter '0' to quit the program at any time
"); while(true) { Console.Write("
Use UK numbering y/n : "); input = Console.ReadLine(); if (!(input.ToLower() == "y" || input.ToLower() == "n")) Console.WriteLine("
 Must be 'y' or 'n', please try again
"); else { if(input.ToLower() == "y") isUK = true; Console.WriteLine("
"); break; } } do { Console.Write("Enter integer : "); input = Console.ReadLine(); isValid = int.TryParse(input, out number); if(!isValid) Console.WriteLine("
 Not an integer, please try again
"); else Console.WriteLine("
 {0}
", NumberToText(number, isUK)); } while(!(isValid && number == 0)); Console.WriteLine("
Program ended"); } public static string NumberToText(int number, bool isUK) { if (number == 0) return "Zero"; string and = isUK ? "and " : ""; // deals with UK or US numbering if (number == -2147483648) return "Minus Two Billion One Hundred "+ and + "Forty Seven Million Four Hundred " + and + "Eighty Three Thousand " + "Six Hundred " + and + "Forty Eight"; int[] num = new int[4]; int first = 0; int u, h, t; System.Text.StringBuilder sb = new System.Text.StringBuilder(); if (number { sb.Append("Minus "); number = -number; } string[] words0 = {"" ,"One ", "Two ", "Three ", "Four ", "Five " ,"Six ", "Seven ", "Eight ", "Nine "}; string[] words1 = {"Ten ", "Eleven ", "Twelve ", "Thirteen ", "Fourteen ", "Fifteen ","Sixteen ","Seventeen ","Eighteen ", "Nineteen "}; string[] words2 = {"Twenty ", "Thirty ", "Forty ", "Fifty ", "Sixty ", "Seventy ","Eighty ", "Ninety "}; string[] words3 = {"Thousand ", "Million ","Billion "}; num[0] = number % 1000; // units num[1] = number / 1000; num[2] = number / 1000000; num[1] = num[1] - 1000 * num[2]; // thousands num[3] = number / 1000000000; // billions num[2] = num[2] - 1000 * num[3]; // millions for(int i = 3; i > 0 ; i--) { if (num[i] != 0) { first = i; break; } } for(int i = first ; i >= 0 ; i--) { if (num[i] == 0) continue; u = num[i] % 10; // ones t = num[i] / 10; h = num[i] / 100; // hundreds t = t - 10 * h; // tens if (h > 0) sb.Append(words0[h] + "Hundred "); if (u > 0 || t > 0) { if (h > 0 || i if (t == 0) sb.Append(words0[u]); else if (t == 1) sb.Append(words1[u]); else sb.Append(words2[t-2] + words0[u]); } if (i != 0) sb.Append(words3[i-1]); } return sb.ToString().TrimEnd(); } } // end class

Krishna Garad · Answer

Check this thread may help you thread

Amount : digits to Word Convertion

Answers (13)