bits as an integer

Ah, my mistake, the method actually takes a base 10 value which then AND'd later in code. So instead of passing 000010, I should be passing 2. :P Thanks anyway for the help. :)

I need it for a COM object I am using - one method of the COM object requires I pass it an int, which is AND'd with another value by the COM object. It's kind of like this: myComObject.setMask(int mask); where the mask is 31 bits (again, which will be AND'd with another value later in code). So the way it is done is to pass up to 31 different 0's and 1's as an integer into the method. An example call would be myComObject.setMask(00001); // which IS different to the COM object than .setMask(1).

Swamii, The question about 3 posts back is the key. Changing the bits to an int in "binary" form will not preserve the individual bit values. You come up with a completely different number. The only way this would work, assuming you could solve leading zero problems and what not, would be to convert your "binary" int back to a string, and parse out the "bits" Myself, I think there is probably a better solution. I can't imagine why you would need an int in "binary" form in the first place. Bill F

Ok, I let me change the wording of my problem. :) I can't preserve the leading 0's after converting several bits to an integer. Example: myStringOfBits = "0001"; myInt = int.Parse(myStringOfBits); MessageBox.Show(myInt.ToString()); // output is "1", when I want it to be "0001"

Int64.Parse didn't work; got an error saying the number was too large. This is beginning to get interesting...is it really possible to represent bits as an integer while preserving the bits? I need to convert the bits 01010010100101 to an int that equals 01010010100101.

Just tried it and the resulting integer is something like 252569461. I need to preserve the bits but represent them as an integer; the string "0100101001001" I want converted to the int 0100101001001. Possible?