Click Once in release application so when minimized in Task Bar it won't open another instance of the application

regor

Hi, I have been looking in different sites to solve my problem but I haven't found any. I am using Visual Studio 2005 .NET The problem: When creating a Setup file, I set the program.cs to do a Mutex thread. Which works when the application is open and left open over the desktop but when minimized to the Task Bar I find that if I click the icon to open the application it does open it rather than show the error message. This is the code I have [STAThread] static void Main() { bool firstInstance; Mutex mutex = new Mutex(false, "Local\\" + "Calculate Time v1.2", out firstInstance); if (firstInstance) { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); Application.Run(new Form1()); } else { MessageBox.Show("An instance of the Time Calculator is already open, please check Taskbar or Desktop"); } } I am not sure if I am doing something wrong, but I think there should be a better way around this or a way to check when the program is minimized? Many Thanks

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Deepak Bhatia17y ago
Accepted answer
Hi regor, Try using this code it will help you, [DllImport("user32.dll")] [return: MarshalAs(UnmanagedType.Bool)] static extern bool SetForegroundWindow(IntPtr hWnd); ///
/// The main entry point for the application. ///
[STAThread] static void Main() { bool createdNew = true; using (Mutex mutex = new Mutex(true, "MyApplicationName", out createdNew)) { if (createdNew) { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); Application.Run(new MainForm()); } else { Process current = Process.GetCurrentProcess(); foreach (Process process in Process.GetProcessesByName(current.ProcessName)) { if (process.Id != current.Id) { SetForegroundWindow(process.MainWindowHandle); break; } } } } }
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regor17y ago
I just needed to add a little messagebox with an example error with that code and it worked perfectly. Thanks :)
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