Copy text box(numeric double) value to txt file.

Question

I am trying to copy the double value from text box to file but values are written multiple times, Meaning if I write 1.5 in text box I get 1 ,1. , 1.5 in text file

private void textBox1_TextChanged(object sender, EventArgs e)
{
StreamWriter sw = new StreamWriter(@"C:\Delta Sigma\Log.txt",true);
sw.WriteLine("Critical Delta Sigma:", textBox1.Text);

sw.Close();

}

Vulpes · Answer

Sure, you could do use AppendAllLines as follows: File.AppendAllLines(@"C:\Delta Sigma\Log.txt", new string[1]{textBox1.Text});

Farhan Shariff · Answer

yeah sure that is the best solution :)..

Vulpes · Answer

If you want to ensure that only one value (the last one) is written to the file, then I'd write it when the application is about to close (i.e. in the main form's FormClosed event-handler).

Farhan Shariff · Answer

When values in text box are deleted and re entered then it is printed multiple times in the file

Farhan Shariff · Answer

Yes I am learning. thanks a lot got it working private void textBox1_Leave(object sender, EventArgs e) { File.AppendAllLines(@"C:\Delta Sigma\Log.txt", new string[1] {"Critical Delta Sigma:" +textBox1.Text }); }

Vulpes · Answer

Select the TextBox in the VS designer and then in the Properties Box find the Leave event and double click it to create a skeleton handler. Now place this line (or whatever you're currently using) in the handler: File.AppendAllLines(@"C:\Delta Sigma\Log.txt", new string[1]{textBox1.Text}); You'll also need to remove the TextChanged handler which you can either do by deleting it in the Properties Box or leaving it in the code but removing the contents.

Farhan Shariff · Answer

How to use Leave event-handler this is not printing in the file private void textBox1_Leave(object sender, EventArgs e) { File.AppendAllText(@"C:\Delta Sigma\Log.txt", "
" + textBox1.Text); }

Vulpes · Answer

There was a missing word in your last post so I'm not sure what you've changed?

Farhan Shariff · Answer

Yeah it was in textBox1_TextChanged function but also I changed the and tried but I have same result. I will try with leave event handler.

Farhan Shariff · Answer

I guess copying it to a double variable and then printing that variable will work. double delta_sigma_critical = double.Parse(textBox1.Text);//ideal value =1.5 Convert.ToDouble(delta_sigma_critical); Let me check

Farhan Shariff · Answer

I want to print ("Critical Delta Sigma:", textBox1.Text); in the file and the value is floating number

Farhan Shariff · Answer

I tried both No it is not working it is printing as 1 1. 1.5

Vulpes · Answer

I don't really understand that unless you are somehow calling the code multiple times. Try instead: File.AppendAllText(@"C:\Delta Sigma\Log.txt", "
" + textBox1.Text);

Vulpes · Answer

Ah, just a moment. Have you by any chance got this code in the TextBox's TextChanged event-handler? If you have then it would explain the output you're seeing in the file. If you want to print it automatically when focus leaves the TextBox, I'd put it in the Leave event-handler instead.

Copy text box(numeric double) value to txt file.

Answers (14)