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Error in code

Amit Maheshwari

Hi friends,
I want to know that i have a some lines code that gave this error were the assignments of 9.0 to g.
Float g = 9.0;
and
g = 9.0;
float is a floating point number yet the line which assigned the 9 value to f compiles correctly while the assignment of 9.0 to g doesn't! This is definitely counter intuitive! The error is
"Error 1 Literal of type double cannot be implicitly converted to type 'float'; use an 'F' suffix to create a literal of this type".

2 Replies

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Karthik Agarwal15y ago
We cannot even compile a program that might involve a loss of precision. Attempting to (implicitly) convert a double to a float will cause a compile error as you said.

We should do one of the following:

* Explicitly cast from double to float:

float d = (float)3.8;

* Use f to indicate that the literal is a float not a double

float d = 9.0F;
Karthik Agarwal15y ago
it will work if you write in the following way.

float g = 9.0F;