help me in exercise

Vitor Ferreira

good all
Someone help me with this exercise, in C:

Implement a program that runs as a list number n n places to the left (if n <0) or right (if n> 0).
Input data:
6
JM
OP
TR
HJ
LF
BG
-2
Output:TR HJ LF BG JM OP

6 Replies

Know the answer? Post it — somebody with the same question will find it here.

Pankaj Kumar Choudhary11y ago
#include
#include
#include
#include
int main(void)
{
        clrscr();
        int n,c,o;

                printf("enter your Number \n");   //Here put no of element in your array
                scanf("%d",&n);
                printf("enter size of each string \n"); //put size of each element
                scanf("%d",&c);
                char *r=new char[c];
                char **p=new char*[n];
        for(int i=0;i        {
                p[i]=new char[2];
                printf(" Enter Your %d Value \n",i+1);
                scanf("%s",p[i]);
    }

                printf("Enter your ordinate \n");
                scanf("%d",&o);

             if((o>=0 && o<=n)||(o<=0 && 0>=-6))
{
             if(o<0)
{
                o=-o;
                while(o>0)
{
                     r=p[0];
        for(int i=0;i{
                    p[i] =p[i+1];
}
                    p[i]=r;

                        o--;
}
}
        else
{
                while(o>0)
{
                r=p[n-1];
        for(int i=n-1;i>0;i--)
{
                    p[i] =p[i-1];
}
                p[i]=r;

                o--;
}
}

                for(int i=0;i                printf("%s ",p[i]);
        }

        for(int i=0;i        delete p[i];

        delete *p;

                getch();
                return 0;
}

in this programe i use the new operator which is part of c++ so for c language you can use malloc
Vulpes11y ago
Try this:

#include
#include

/* let's say */
#define MAX_CONTACTS 20

void rotate_left_one(char contacts[MAX_CONTACTS][3], int number)
{
int i;
char first[3];
strcpy(first, contacts[0]);
for(i = 1; i < number; i++) strcpy(contacts[i - 1], contacts[i]);
strcpy(contacts[number - 1], first);
}

void rotate_right_one(char contacts[MAX_CONTACTS][3], int number)
{
int i;
char last[3];
strcpy(last, contacts[number - 1]);
for(i = number - 2; i >= 0; i--) strcpy(contacts[i + 1], contacts[i]);
strcpy(contacts[0], last);
}

void rotate_multi(char contacts[MAX_CONTACTS][3], int number, int places)
{
int i ;
places = places % 6;

if (places < 0)
{
places = -places;
for(i = 0; i < places; i++) rotate_left_one(contacts, number);
}
else if (places > 0)
{
for(i = 0; i < places; i++) rotate_right_one(contacts, number);
}
}

int main()
{
char contacts[MAX_CONTACTS][3];
int i, number, ord;
printf("enter the number of contacts you want to enter, max 20:\n");
scanf("%d", &number);
getchar(); // clear new line character from buffer
if (number < 1) number = 1;
if (number > 20) number = 20;

for(i = 0; i < number; i++)
{
printf("%d contact: ", i + 1);
gets(contacts[i]);
}

printf("ordination: ");
scanf("%d", &ord);
getchar();
rotate_multi(contacts, number, ord);

/* print results */
printf("\nOutput: ");
for(i = 0; i < number; i++) printf("%s ", contacts[i]);
printf("\n");
system("pause");
return 0;
}
Jignesh Trivedi11y ago
This is C# code you may convert it into C code by replacing Console.WriteLine to printf() and Console.ReadLine to scanf()
and int.TryParse(Console.ReadLine(), out data); must be replace with scanf("%d", &data);
hope this will help you.
Jignesh Trivedi11y ago
hi,
Try following code
Console.WriteLine("enter the number of contacts you want to enter:");
int data = 0;
int.TryParse(Console.ReadLine(), out data);
string[] allData = new string[data];
for (var i = 1; i <= data; i++)
{
    Console.WriteLine(i + " contact:");
    allData[i - 1] = Console.ReadLine();
}
Console.WriteLine("ordination:");
int o;
int.TryParse(Console.ReadLine(), out o);
for (var i = 1; i <= data; i++)
{
    Console.WriteLine(allData[o]);
    o = o + 1;
    if(o>=data)
    {
        o = 0;
    }
}
hope this will help you.
Vitor Ferreira11y ago
input

enter the number of contacts you want to enter:
6
1 contact: JM
2 contact: OP
3 contact: TR
4 contact: HJ
5 contact: LF
6 contact: BG
ordination: -2

Output: TR HJ LF BG JM OP

The contacts are sorted the TH to OP
Jignesh Trivedi11y ago
Not understand the question...

can you please provide more information?