i craete an android application with four buttons in the first interface and i need each button to open another screen when clicked i did it correctly with the first button using this code 
- using Android.App;  
 - using Android.Widget;  
 - using Android.OS;  
 -   
 - namespace fitness_ghadi  
 - {  
 -     [Activity(Label = "fitness_ghadi", MainLauncher = true , Icon ="@drawable/icon")]  
 -     public class MainActivity : Activity  
 -     {  
 -         protected override void OnCreate (Bundle bundle)  
 -         {  
 -             base.OnCreate(bundle);  
 -               
 -             SetContentView(Resource.Layout.Main);  
 -             Button button = FindViewById<Button>(Resource.Id.second);  
 -             button.Click += delegate {  
 -                 StartActivity(typeof(second));  
 -             };  
 -         }  
 -          
 -     }  
 - }  
 
and this 
- using System;  
 - using System.Collections.Generic;  
 - using System.Linq;  
 - using System.Text;  
 -   
 - using Android.App;  
 - using Android.Content;  
 - using Android.OS;  
 - using Android.Runtime;  
 - using Android.Views;  
 - using Android.Widget;  
 -   
 - namespace fitness_ghadi  
 - {  
 -     [Activity(Label = "second")]  
 -     public class second : Activity  
 -     {  
 -         protected override void OnCreate(Bundle savedInstanceState)  
 -         {  
 -             base.OnCreate(savedInstanceState);  
 -             SetContentView(Resource.Layout.Second);  
 -             Button button = FindViewById<Button>(Resource.Id.First);  
 -             button.Click += delegate {  
 -                 StartActivity(typeof(MainActivity));  
 -             };  
 -               
 -         }  
 -     }  
 - }  
 
but when i try to make the same code for the rest buttons it did't work i found errors , how can i do it please?