Loading

How to concatenate the "string" and "int" into int type vari

How to concatenate the "string" and "int" into int type vari

arslan elahi

13y2.2kVisual Basic .NET

concatenate the "string" and "int" into int type variable

e.g

int a=10;

string b="abc"

a = a+ b;

is it possible???

how???

5 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes13y ago
It's not working on my machine:

Unhandled Exception: System.FormatException: Input string was not in a correct f
ormat.
at System.Number.StringToNumber(String str, NumberStyles options, NumberBuffe
r& number, NumberFormatInfo info, Boolean parseDecimal)
at System.Number.ParseInt32(String s, NumberStyles style, NumberFormatInfo in
fo)

However, if you specify that the string represents a hexadecimal number, then it will work as the code is equivalent to what I posted in the first place:

int a = 10;
object b = "abc";
a= a + Convert.ToInt32(b.ToString(), 16); // a is 2758
arslan elahi13y ago
i've done with object

int a=10;
object b="abc";

a=a+ Convert.ToInt32(b.toString());

it is working
Vulpes13y ago
The equivalent code in VB.NET:

Dim a As Integer = 10
Dim b As String = "abc"
a = a + b

compiles OK with Option Strict Off but produces a run time exception because "abc" can't be parsed to a double.
arslan elahi13y ago
it is working in VB
i want to convert it in C#
Vulpes13y ago
It's not possible as it stands because a + b yields the string "10abc" which isn't an int and can't even be parsed to an int.

However, the following does work:

int a = 10;
string b = "abc";
a = a + Convert.ToInt32(b, 16);

The result is 2758.

The reason this works is because "abc" can be parsed to an hexadecimal integer which is equivalent to 2748 decimal. So adding 10 gives a result of 2758.