How to insert record in two different tables on a button clk
I have two tables product(productId,productName,productRate) and ID(id)...i want to insert record on a button click.I want to insert record into product table and want productId to insert in ID table on same button click.
Satyapriya NayakPosted Mar 9, 2013, 7:01 AM
ALTER PROCEDURE insert1
(@custid varchar(50),@custname varchar(50),@custaddress varchar(50),@prodid varchar (50))
AS
insert Customer(custid,custname,custaddress,prodid) values (@custid,@custname,@custaddress,@prodid)
ALTER PROCEDURE insert2
(@prodid varchar(50),@prodname varchar(50),@price int)
AS
insert Product(prodid,prodname,price) values (@prodid,@prodname,@price)
Default.aspx code
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %>
Default.aspx.cs code
using System;
using System.Configuration;
using System.Data;
using System.Linq;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Xml.Linq;
using System.Data.SqlClient;
public partial class _Default : System.Web.UI.Page
{
string strConnString = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString;
SqlCommand com;
protected void btn_insert_Click(object sender, EventArgs e)
{
SqlConnection con = new SqlConnection(strConnString);
com = new SqlCommand("insert1", con);
com.CommandType = CommandType.StoredProcedure;
com.Parameters.Add("@custid", SqlDbType.VarChar).Value = TextBox1.Text;
com.Parameters.Add("@custname", SqlDbType.VarChar).Value = TextBox2.Text;
com.Parameters.Add("@custaddress", SqlDbType.VarChar).Value = TextBox3.Text;
com.Parameters.Add("@prodid", SqlDbType.VarChar).Value = TextBox4.Text;
con.Open();
com.ExecuteNonQuery();
con.Close();
com = new SqlCommand("insert2", con);
com.CommandType = CommandType.StoredProcedure;
com.Parameters.AddWithValue("@prodid", SqlDbType.VarChar).Value = TextBox4.Text;
com.Parameters.Add("@prodname", SqlDbType.VarChar).Value = TextBox5.Text;
com.Parameters.Add("@price", SqlDbType.Int).Value = TextBox6.Text;
con.Open();
com.ExecuteNonQuery();
con.Close();
Label7.Text = "Record Successfully Inserted";
TextBox1.Text="";
TextBox2.Text="";
TextBox3.Text="";
TextBox4.Text="";
TextBox5.Text="";
TextBox6.Text="";
}
}