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Initialize a multidimensional array

Ronald Gans

Somehow this eludes me:

byte [][][] multiArray;

I would like to have it end up like this:

multiArray[a][b][c]

ie., the left most dimension have a elements, middle, b which are all of length c.

THANKS!!

RON

OF COURSE, right after I posted it I remembered the syntax; that was my issue. And THANKS to those who sent me some pointers about it.

RON

1 Reply

Know the answer? Post it — somebody with the same question will find it here.

Shahan Ayyub15y ago
try:

int a=3, b=3, c=3; //just an example
byte[,,] multiArray = new byte[a,b,c];