instance method that convert from otherbase to base 10

Prince

am writing a class, within my class i need an instance method(without using library routine) that convert from other base to base 10
private int otherbase2Decimal(int Decimal, int otherbase)
{
//want my code to handle exception if base <2 or >10)
try
{
if ((otherbase < 2) || (otherbase > 10))
}
catch(FormatException)
{
Console.WriteLine("otherbase must be in range 2-10");
}
else
{ if (Decimal !=0)
{.........return sum;// need help/code on d algorithm that will return sum as decimal num.thanks
}
}

3 Replies

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Sam Hobbs16y ago
Accepted answer
Start by using the low-order digit as-is; so if the base is 4 and the number is 321, then start with 1. Then for each position moving from low-order to high-order, multipy the value that 1 would be in each position by the base and then multipy the digit in that position by the value that 1 would be in that position. In other words, the value of 1 in the second position is 4, so multipy 2*4 and add that to the result. Then multiply the value that 1 would be in that position; 1 in the second position would be 4 so multiply 4 times four to get 16. Multiply 3 times 16 and add that to the result. If there was a fourth digit, then the value of 1 in the fourth position is 4*16 or 64.

So 321 in base 4 is 1+(2*4)+(3*16), correct?
Prince16y ago
thinking of treating otherbase as string, multiplying value of each string index with (otherbase raise to power of index)......
Sam Hobbs16y ago
Why not use a library routine? I assume the reason why is that this is a class assignment. The best way to help you is to help you figure it out yourself. What have you done to figure it out? How do you think it needs to be done?