Method invoking

Question

Sir, I am not understanding the below code of method. pls explain. static void PrintNumber(int numberParam) { // Modifying the primitive-type parameter numberParam = 5; Console.WriteLine("in PrintNumber() method, after " + "modification, numberParam is: {0}", numberParam); } Invocation of the method from Main(): static void Main() { int numberArg = 3; // Copying the value 3 of the argument numberArg to the // parameter numberParam PrintNumber(numberArg); Console.WriteLine("in the Main() method numberArg is: " + numberArg); } The result from the above line is printed below: in PrintNumber() method, after modification, numberParam is: 5 in the Main() method numberArg is: 3 1. Pls explain what is method declaration, invocation, argument in simple words.

Dharmraj Thakur · Answer

Your second statement is fine. But you directly implemented your method so declaration is not there. So void PrintNumber(int numberParam){ } is not declaration because of body is there.

harish reddy · Answer

Couple of questions: 1. Thanks. you said " In your case method declaration is not avaialble" . i thought i declared the method like this .void PrintNumber(int numberParam). Pls correct me if wrong. 2. Also can we say Declaration: declaring the method Implementation: writing the code inside the method Invocation: calling the method elsewhere to use it.

Dharmraj Thakur · Answer

1. Method declaration: Just declaration method with its signature without having boday is called method declaration. In your case method declaration is not avaialble Eg: void PrintNumber(int numberParam); //this will make sense what is the prototype of any method like what is expecting as argument and what will it return? 2. Method Implementation: When method having body. Means actual work of method written inside curly brackes.... static void PrintNumber(int numberParam) { // Modifying the primitive-type parameter numberParam = 5; Console.WriteLine("in PrintNumber() method, after " + "modification, numberParam is: {0}", numberParam); } 3. Method invocation: Just call the readymade method and it will perform as written logic is called method invocation. PrintNumber(1); // here you have to pass actual values in argument and catch whatever it return (void if no return value) 4. Argument: Argument is parameters of any method which can have zero, one or more. You can pass any values to the method. PrintNumber( 1 ); //caller will call with passing actual values static void PrintNumber( int numberParam ) // values will receive here... arguments valriable will hold the values passed from caller. {}

Method invoking

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