not executing code after Task in async/await programming

Ravi Kiran Chanduri

Hi ,

I am trying to understand the actual use of asyn/await in c# and have gone through few articles and tried with an example as below.

I am able to see third method's result , but the code after string message = await delayingMethodCall;

is not executing.

Can someone explain me the issue here?

Thanks in Advance

Ravi.

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Amit Gupta6y ago
Change MethodTwo's body to the below one
public async Task MethodTwo()
        {
            Task<string> delayingMethodCall = new Task<string>(DelayingMethod);
            Console.WriteLine("methodTwo call started");
            delayingMethodCall.Start();
            string message =  delayingMethodCall.Result;
            Console.WriteLine(message);
            Console.WriteLine("methodTwo called");
            Console.ReadKey();
        }
Reason:
Didn't dig much into this but I found the issue in below

await delayingMethodCall;

You just called the await function without starting the Task and to get the output, you should use obj.Result.

Hope your doubts were cleared.

Good Luck!
Ravi Kiran Chanduri6y ago
Hi Amit,

no luck even after the change
Amit Gupta6y ago
This is because, you didn't started the task, use delayingMethodCall.Start(); and inspite of using Thread.Sleep(..), use Task.Delay(..)